Momo with mass m is sliding down an inclined plane that makes an angle D relative to the horizontal. The coefficient of kinetic friction between Momo ane the inclined plane is µk. Obtain an expression for Momo's acceleration along the incline. Assign a rotated Cartesian plane so that the acceleration is along the positive x-axis and the normal force is along the positive y-axis. The component of the weight parallel to Momo's acceleration is wx = mg Ф. The magnitude of the frictional force is f%= Hk The normal force on Momo is n = mg With these expressions and applying Newton's second law, we arrive at an expression for Momo's acceleration: a = - Hk

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Chapter1: Units, Trigonometry. And Vectors
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Momo with mass m is sliding down an inclined plane that makes an angle Φ relative to the horizontal. The coefficient of kinetic friction between Momo and the inclined plane is μk. Obtain an expression for Momo's acceleration along the incline.

Assign a rotated Cartesian plane so that the acceleration is along the positive x-axis and the normal force is along the positive y-axis.

The component of the weight parallel to Momo's acceleration is wx = mgBlank 1Φ.

The magnitude of the frictional force is f = μkBlank 2.

The normal force on Momo is n = mgBlank 3Φ.

With these expressions and applying Newton's second law, we arrive at an expression for Momo's acceleration:

a = Blank 4 ( Blank 5 - μkBlank 6 )

Momo with mass m is sliding down an inclined plane that makes an angle D relative to the horizontal. The coefficient of kinetic friction between Momo and
the inclined plane is Pk. Obtain an expression for Momo's acceleration along the incline.
Assign a rotated Cartesian plane so that the acceleration is along the positive x-axis and the normal force is along the positive y-axis.
The component of the weight parallel to Momo's acceleration is wx = mg
Ф.
The magnitude of the frictional force is f= Hk
The normal force on Momo is n = mg
With these expressions and applying Newton's second law, we arrive at an expression for Momo's acceleration:
a =
- Pk
Transcribed Image Text:Momo with mass m is sliding down an inclined plane that makes an angle D relative to the horizontal. The coefficient of kinetic friction between Momo and the inclined plane is Pk. Obtain an expression for Momo's acceleration along the incline. Assign a rotated Cartesian plane so that the acceleration is along the positive x-axis and the normal force is along the positive y-axis. The component of the weight parallel to Momo's acceleration is wx = mg Ф. The magnitude of the frictional force is f= Hk The normal force on Momo is n = mg With these expressions and applying Newton's second law, we arrive at an expression for Momo's acceleration: a = - Pk
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