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A 50 kg crate sits on a flat horizoral floor. A rope is attached and pulled horizontally to the right. Let T, N and F be the magnitude of the tension force (T), the normal force (N) and the friction force (F) respectively. Take acceleration due to gravity to be 10 ms-². a) b) c) Copy the diagram and show on it the direction of T, N and F. Explain why N d) = mg. The maximum magnitude of the friction of the crate on the floor is directly proportional to the magnitude of the normal force. That is, Fmax = AN where is a non-negative real number. It is found that the crate begins to move when the tension exceeds 100 Newtons. Find the value of λ. The rope is now held up by a man so that the angle of elevation of the rope is 0. The man now pulls the rope to the right, keeping the end of the rope at a constant height above the floor. 0 Given that the value of λ does not change, show that in this situation Fmax is reached when: T = 500 5 cos 0+ sin 8

A 50 kg crate sits on a flat horizoral floor. A rope is attached and pulled horizontally to the right. Let T, N and F be the magnitude of the tension force (T), the normal force (N) and the friction force (F) respectively. Take acceleration due to gravity to be 10 ms-². a) b) c) Copy the diagram and show on it the direction of T, N and F. Explain why N d) = mg. The maximum magnitude of the friction of the crate on the floor is directly proportional to the magnitude of the normal force. That is, Fmax = AN where is a non-negative real number. It is found that the crate begins to move when the tension exceeds 100 Newtons. Find the value of λ. The rope is now held up by a man so that the angle of elevation of the rope is 0. The man now pulls the rope to the right, keeping the end of the rope at a constant height above the floor. 0 Given that the value of λ does not change, show that in this situation Fmax is reached when: T = 500 5 cos 0+ sin 8

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Hi, I need help with part d of this question. Thanks.
A 50 kg crate sits on a flat horizortal floor. A rope is attached and pulled horizontally to the right. Let T, N and F be the magnitude of the tension force (T), the normal force (N) and the friction force (F) respectively. Take acceleration due to gravity to be 10 ms-². a) b) Copy the diagram and show on it the direction of T, N and F. Explain why N d) = mg. The maximum magnitude of the friction of the crate on the floor is directly proportional to the magnitude of the normal force. That is, Fmax = AN where is a non-negative real number. It is found that the crate begins to move when the tension exceeds 100 Newtons. Find the value of 2. The rope is now held up by a man so that the angle of elevation of the rope is 0. The man now pulls the rope to the right, keeping the end of the rope at a constant height above the floor. X Given that the value of λ does not change, show that in this situation Fmax is reached when: T = 500 5 cos 0+ sin 8
Transcribed Image Text:A 50 kg crate sits on a flat horizortal floor. A rope is attached and pulled horizontally to the right. Let T, N and F be the magnitude of the tension force (T), the normal force (N) and the friction force (F) respectively. Take acceleration due to gravity to be 10 ms-². a) b) Copy the diagram and show on it the direction of T, N and F. Explain why N d) = mg. The maximum magnitude of the friction of the crate on the floor is directly proportional to the magnitude of the normal force. That is, Fmax = AN where is a non-negative real number. It is found that the crate begins to move when the tension exceeds 100 Newtons. Find the value of 2. The rope is now held up by a man so that the angle of elevation of the rope is 0. The man now pulls the rope to the right, keeping the end of the rope at a constant height above the floor. X Given that the value of λ does not change, show that in this situation Fmax is reached when: T = 500 5 cos 0+ sin 8
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