Use the formula for the binomial series: (1+x)™ = m(m-1) x²+ 2! m(m–1)--(m-k+l),k + 1+ mx + + ... ... k! m(m-1)..(m-k+1) 1+ Ek=1 x if |x| < 1 k! to obtain the Maclaurin series for V1+ x. 1 1-r + S(-1)°• 13 · 20…(7k – 8) 7* k! k=2 00 1+r+ S(-1)k+1© • 13 · 20…(7k – 8) 1 + x + 7k k! k=2 13 · 20...(7k – 8) 1+ E(-1)*13 - 7k k! k=1 13 · 20..(7k – 8) 1 + k! k=1
Use the formula for the binomial series: (1+x)™ = m(m-1) x²+ 2! m(m–1)--(m-k+l),k + 1+ mx + + ... ... k! m(m-1)..(m-k+1) 1+ Ek=1 x if |x| < 1 k! to obtain the Maclaurin series for V1+ x. 1 1-r + S(-1)°• 13 · 20…(7k – 8) 7* k! k=2 00 1+r+ S(-1)k+1© • 13 · 20…(7k – 8) 1 + x + 7k k! k=2 13 · 20...(7k – 8) 1+ E(-1)*13 - 7k k! k=1 13 · 20..(7k – 8) 1 + k! k=1
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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help me asap pls i'm having a hard time for number 2 less than 30 mins.
![Use the formula for the binomial series:
(1 + x)" =
1+ mx +
2!
m(m-1)
m(m-1).(m-k+1) k
+
+ ...
+ ...
k!
1+ Σ
m(m-1)..(m-k+1)
ik=1
|지 < 1
if
k!
to obtain the Maclaurin series for V1 + x.
6· 13 · 20.(7k – 8)
1
1
-++ Σ(-1)
7*k!
k=2
1
1+ =x +
デー
E(-1)*+16 · 13 · 20-(7k – 8)
7k k!
k=2
13 · 20...(7k – 8)
1+ E(-1)*-
7k k!
k=1
13 · 20..(7k – 8)
1+ >
k!
k=1
1
1 +
+ E(-1)k+10 · 13 · 20…(7k – 8)
k!
k=2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff426c0c2-1915-4c59-8ca6-58b1f9fc733f%2Fe7d2667b-062d-4941-86f3-0f5ba1ca67ac%2Fcjlgl0n_processed.png&w=3840&q=75)
Transcribed Image Text:Use the formula for the binomial series:
(1 + x)" =
1+ mx +
2!
m(m-1)
m(m-1).(m-k+1) k
+
+ ...
+ ...
k!
1+ Σ
m(m-1)..(m-k+1)
ik=1
|지 < 1
if
k!
to obtain the Maclaurin series for V1 + x.
6· 13 · 20.(7k – 8)
1
1
-++ Σ(-1)
7*k!
k=2
1
1+ =x +
デー
E(-1)*+16 · 13 · 20-(7k – 8)
7k k!
k=2
13 · 20...(7k – 8)
1+ E(-1)*-
7k k!
k=1
13 · 20..(7k – 8)
1+ >
k!
k=1
1
1 +
+ E(-1)k+10 · 13 · 20…(7k – 8)
k!
k=2
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