The function f(t)-D1 if t<3, f(t)=sin t if 35 can be presented as: O f (t) = 1+u (t – 3) + sin t (u (t – 3) – u (t – 5)) + tu (t – 5) O f (t) = 1- u (t – 3) + sin t (u (t – 3) – u (t – 5)) + tu (t – 5) O f (t) = -u (t - 3) + sin t · (u (t - 3) – u (t – 5)) + tu (t – 5) O f(t) = u (t – 3) + sint (u (t – 3) – u (t – 5)) + tu (t – 5) - IL O None of the above

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Chapter2: Second-order Linear Odes
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The function f(t)-1 if t<3, f(t)=sin t if 3<t<5, f(t)=t if t>5 can be presented as:
O f (t) = 1+u (t – 3) + sin t (u (t – 3) – u (t – 5)) + tu (t – 5)
O f (t) = 1- u (t – 3) + sin t · (u (t – 3) – u (t – 5)) + tu (t – 5)
O f (t) = -u (t – 3) + sint · (u (t – 3) – u (t – 5)) + tu (t – 5)
O f (t) = u (t – 3) + sin t · (u (t – 3) – u (t – 5)) + tu (t – 5)
- 1L
O None of the above
f (t) = u (t – 3) + sin t - u (t – 3) + tu (t – 5)
O f (t) = 1- u (t – 3) + sin t · u (t – 3) + tu (t – 5)
Transcribed Image Text:The function f(t)-1 if t<3, f(t)=sin t if 3<t<5, f(t)=t if t>5 can be presented as: O f (t) = 1+u (t – 3) + sin t (u (t – 3) – u (t – 5)) + tu (t – 5) O f (t) = 1- u (t – 3) + sin t · (u (t – 3) – u (t – 5)) + tu (t – 5) O f (t) = -u (t – 3) + sint · (u (t – 3) – u (t – 5)) + tu (t – 5) O f (t) = u (t – 3) + sin t · (u (t – 3) – u (t – 5)) + tu (t – 5) - 1L O None of the above f (t) = u (t – 3) + sin t - u (t – 3) + tu (t – 5) O f (t) = 1- u (t – 3) + sin t · u (t – 3) + tu (t – 5)
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