Use the following information to answer the next question. An electron, initially travelling at 2.0 x 106 m/s horizontally, enters a region exactly halfway between two 4.0-cm long parallel plates. The plates are 2.00 cm apart from each other with a potential difference of 4.00 V. The electron leaves the region between the parallel plates with a deflection upwards, as shown in the diagram below. dx = 4.0 cm Plate #1 e Vi Plate #2 Note: Gravitational, frictional and edge effects are negligble and this diagram is not drawn to scale. 4a) Determine the charge (postive / negative) Plate #2.

Use the following information to answer the next question. An electron, initially travelling at 2.0 x 106 m/s horizontally, enters a region exactly halfway between two 4.0-cm long parallel plates. The plates are 2.00 cm apart from each other with a potential difference of 4.00 V. The electron leaves the region between the parallel plates with a deflection upwards, as shown in the diagram below. dx = 4.0 cm Plate #1 e Vi Plate #2 Note: Gravitational, frictional and edge effects are negligble and this diagram is not drawn to scale. 4a) Determine the charge (postive / negative) Plate #2.

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter5: Electric Charges And Fields

Section: Chapter Questions

Problem 52P: Suppose Earth and the Moon each carried a net negative charge Q . Approximate both bodies as point...

See similar textbooks

Similar questions

Please fill in the blanks. Suppose an electron (q equals negative e equals negative 1.6 cross times 10 to the power of negative 19 end exponent space text C end text space,m equals 9.1 cross times 10 to the power of negative 31 end exponent space text kg end text) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for the final speed of the electron. Express numerical answer in two significant figures.
An electron is fired at a speed v, = 4.2 x 105 m/s and at an angle 6 = 37° between two parallel conducting plates as shown in the figure. If s = 1.8 mm and the voltage difference between the plates is AV = 99.6 V, determine how close, w, the electron will get to the bottom plate. Put your answer in meters and include at 6 decimal places in your answer. Do not include units. The x-axis of the coordinate system is in the middle of the parallel plate capacitor.
Path of trajectory AV An electron is fired at a speed vj = 4.7 x 106 m/s and at an angle 0; = 37.1° between two parallel conducting plates as shown in the figure. If s = 2 mm and the voltage difference between the plates is AV = 99.6 V, determine how close, w, the electron will get to the bottom plate. Put your answer in meters and include at 6 decimal places in your answer. Do not include units. The x-axis of the coordinate system is in the middle of the parallel plate capacitor.
An electron is fired at a speed v 4.3 x 10 m/s and at an angle 8 = 39.7 between two parallel conducting plates as shown in the figure. If s 1.7 mm and the voltage difference between the plates is AV= 99.8 V, determine how close, w. the electron will get to the bottom plate. Put your answer in meters and include at 6 decimal places in your answer. Do not include units. The x-axis of the coordinate system is in the middle of the parallel plate capacitor. Round your answer to 6 decimal places.
Directions: Solve for the given problems. Show your complete solutions. Round off your answers into 3 significant figures. 1. A potential difference of 4.80 kV is established between parallel plates in air. If the air becomes electrically conducting when the electric field exceeds 3.00 x 106 V/m, what is the minimum separation distance?
help with physics please
Use the following information to answer the next three questions The battery below has a potential difference of 592 V. 4.00 cm V 4.00 cm А 4.00 cm 8. Starting from rest at the top plate, with what velocity would an alpha (x²+ ) particle m hit the bottom plate? The answer can be written in the form a.bc x 10" s. The value of a.bc is (Record your three-digit answer in the numerical-response section below.) 0000 Your answer:
How to compute number 1 if the answer is in the problem is 7 MV
An electron is fired at a speed vi = 3.1 × 106 m/s and at an angle θi = 36.8° between two parallel conducting plates as shown in the figure. If s = 1.8 mm and the voltage difference between the plates is ΔV = 98.8 V, determine how close, w, the electron will get to the bottom plate. Put your answer in meters and include at 6 decimal places in your answer. Do not include units. The x-axis of the coordinate system is in the middle of the parallel plate capacitor
need help on a
Help me please
A parallel-plate capacitor has the capacitance of C = 10 µF when the distance of the two plates is d = 5 cm. A battery with the emf = 3 V is used to charge the capacitor. %3D 1. How much charge can be put on the parallel-plate capacitor? (in the unit of pC) Q = Submit Answer Tries 0/2 Now, consider the following two cases separately: Case 1: if the emf stays connected, but the distance of the parallel plates is changed to d = 80 cm. 2. What is the new capacitance C1 and how much is the charge Q1in the capacitor? C1 = µF %D Q1 = %3D Submit Answer Tries 0/2 Case 2: After the initial charging, the emf is removed. Therefore, the amount of charge you calculated from the question #1 remains in the capacitor. Now, again, the distance of the parallel plates is changed to d1 = 80 cm. 3. What is the potential difference V1 across the capacitor? V1 = %3D