Use the following data to run a two-tailed t-test in R. Does the mean equal 3? State the appropriate null and alternative hypothesis. [1] 2.698453 2.575547 3.344457 3.675068 3.490855 3.692199 2.693355 2.682515 [9] 3.838997 2.377862 3.228593 2.243595 2.708181 2.133151 2.540468 3.818521 [17] 2.890985 3.850087 2.552904 3.040451
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- The table below lists leading digits of 317 inter-arrival Internet traffic times for a computer, along with the frequencies of leading digits expected with Benford's law. When using these data to test for goodness-of-fit with the distribution described by Benford's law, identify the null and alternative hypotheses. Leading Digit Benford's Law Leading Digits of Inter-Arrival Traffic Times 1 2 3 4 5 7 8 9. 30.1% 17.6% 12.5% 9.7% 7.9% 6.7% 5.8% 5.1% 4.6% 76 62 29 28 21 22 Choose the correct answer below. O A. Ho: At least one of the proportions is different from the others. H,: p, = 0.301 and p, = 0.176 and p3 = 0.125 and and pg = 0.046 O B. Ho: None of the proportions are equal to the given claimed value. H,: p, = 0.301 and p, = 0.176 and p3 = 0.125 and ... and pg = 0.046 O C. Ho: p, = 0.301 and p, = 0.176 and H,: None of the proportions are equal to the given claimed value. P3 = 0.125 and and pa = 0.046 O D. Ho: p, = 0.301 and p, = 0.176 and p3 = 0.125 and and = 0.046 ... H4: At least…The following hypotheses are given to determine an One-Tail testing. H0: p≤0 Ha: p >0 A random sample of 10 paired observations indicated a correlation (r) of .35. Can we conclude that the correlation in the population is greater than zero by performing the t-statistic? By using the .05 significance level, what is the p-value or critial value?____________ What is your decision regarding Ho or the null hypothosis? The Airline Passenger Association studied the relationship between the number of passengers on a particular flight and the cost of the flight. It seems logical that more passengers on the flight will result in more weight and more luaggage, which in turn will result in higher fuel costs. For a sample of 13 flights, the correlation between the number of passengers and total fuel cost was .37. Is it reasonable to conclude that there is positive association in the population between the two variables? H0: p≤0 Ha: p >0 The…Find the expected count under the null hypothesis. 19. A sociologist was interested in determining if there was a relationship between the age of a young adult (18 to 35 years old) and the type of movie preferred. A random sample of 93 adults revealed the following data. Use a Chi-Square independence test to determine if age and type of movie preferred are independent at the 5% level of significance. 30-35 years old Totals 24-29 years old 15 18-23 years old Drama 8. 11 34 Science Fiction 12 10 8. 30 8. 12 29 Comedy Totals 29 33 31 93 Provided the assumptions of the test are satisfied, find the expected number of 24-29 year-olds who prefer comedies under the null hypothesis. a) 8 b) 11.56 c) 10.29 d) 7.34
- Test the claim that the mean GPA of night students is smaller than 2.5 at the 10% significance level. The population standard deviation for this group is known to be 0.16. The null and alternative hypotheses for this test are: Но: д 2.5 Нд:д > 2.5 НА:Д < 2.5 The test is: left-tailed right-tailed Based on a sample of 30 people, the sample mean GPA was 2.47. Hint: Before you find the p-value below, calculate the test statistic to two decimal places. The p-value is: (to 4 decimals) The significance level as a decimal is: Based on this we O fail to reject the null hypothesis, Ho O reject the null hypothesis, HoK In a random sample of males, it was found that 23 write with their left hands and 212 do not. In a random sample of females, it was found that 58 write with their left hands and 442 do not. Use a 0.05 significance level to test the claim that the rate of left-handedness among males is less than that among females. Complete parts (a) through (c) below. a. Test the claim using a hypothesis test. Consider the first sample to be the sample of males and the second sample to be the sample of females. What are the null and alternative hypotheses for the hypothesis test? O A. Ho: P₁ P2 H₁: P₁ P2 O D. Ho: P₁ P2 H₁: P₁ P2 Z= OB. Ho: P1 P2 H₁: P₁ P2 Identify the test statistic. -0 (Round to two decimal places as needed.) Identify the P-value. OE Ho: P1 H₁: P₁ The P-value is hypothesis. There P-value= (Round to three decimal places as needed.) What is the conclusion based on the hypothesis test? P₂ P₂ OC. Ho: P₁ SP2 H₁: P₁ P₂ OF. Ho: P1 P2 H₁: P₁ P2 the significance level of a = 0.05, so Because…A child psychologist observed that in a random sample of 60 toddlers, 27 preferred to play with masculine toys, 19 preferred to play with feminine toys and 14 preferred to play with gender neutral toys. A chi-square test of the null hypothesis is provided below: Category Observed N Expected N Residual Masculine Toys 27 20 7 Feminine Toys 19 20 -1 Neutral Toys 14 20 -6 Total 60 Test Statistics CATEGORY Chi-Square 4.300 df = 2 Asymp. Sig. .116 a. Why is the chi-square goodness-of-fit the appropriate test? Explain. b. Is there a significant preference for these three types of toys? Explain. c. Using the information in the tables above, write an APA style results section.
- The state of CT claims that the average time on death row is 15 years. A random survey of 75 death row inmates revealed that the average length of time on death row is 16.6 years with a standard deviation of 5.8 years. Conduct a hypothesis to test the state of CT's claim. t test mean two tail test p value = ____________ What is the decision?Test the claim about the differences between two population variances a and o at the given level of significance a using the given sample statistics. Assume that the sample statistics are from independent samples that are randomly selected and each population has a normal distribution. Claim: o so, a = 0.05 Sample statistics: s, = 705, n, =3, s = 368, n, = 9 Find the null and alternative hypotheses. OA Hoio> Hạ: o so3 OC. Hoi o z0 H,: o3Nine students took the SAT. Their scores are listed below. Later on, they read a book on test preparation and retook the SAT. Their new scores are listed below. Assume that the distribution is normally distributed. 1. Can it be concluded at α = .05 that the scores have changed? Do the hypothesis test. 2. Construct a 95% confidence interval for μd. Student 1 2 3 4 5 6 7 8 9 Before Reading 720 860 850 880 860 710 850 1200 950 After Reading 740 860 840 920 890 720 840 1240 970COMPUTE the standard error of the mean?Determine the critical value(s) for a one-mean z-test. Draw a graph that illustrates your answer. A left-tailed test with a = 0.03. Click here to view page 1 of the standard normal table. Click here to view page 2 of the standard normal table. The critical value(s) is (are) (Round to two decimal places as needed. Use a comma to separate answers as needed.) Choose the correct graph of the hypothesis test below. O A. O B. Reject Ho 0.015 Do not reject Ho 0.985 Rej. Ho 0.03 Do not reject Ho 0.94 T 0 Rej. Ho Q 0.03 /₂0 O C. Do not reject Ho W 0.97 Reject Ho 0.03SEE MORE QUESTIONS