Answered: To test this claim the null hypothesis…

Math

Statistics

To test this claim the null hypothesis is: Select one: H0: µ ≤ 30 H0: µ ≤ 31.4 H0: µ ≥ 30 H0: µ ≥ 31.4

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

A sample mean, sample standard deviation, and sample size are given. Perform the required hypothesis test about the mean, μ, of the normal population from which the sample was drawn. H0: μ = 132, Ha: μ ≠ 132, x=137 , s = 14.2, n = 20, α = 0.10 P-value = 0.0582. Reject H0. There is sufficient evidence to conclude that the mean is different from 132. P-value = 0.0659. Reject H0. There is sufficient evidence to conclude that the mean is different from 132. P-value = 0.1318. Do not reject H0. There is not sufficient evidence to conclude that the mean is different from 132. P-value = 0.1164. Do not reject H0. There is not sufficient evidence to conclude that the mean is different from 132.
A large airline company called Tale Winds monitors customer satisfaction by asking customers to rate their experience as a 1, 2, 3, 4, or 5, where a rating of 1 means "very poor" and 5 means "very good". The customers' ratings have a population mean of u=3.88, with a population standard deviation of o = 1.38. Suppose that we will take a random sample of n = 8 customers' ratings. Let x represent the sample mean of the 8 customers' ratings. Consider the sampling distribution of the sample mean x. Complete the following. Do not round any intermediate computations. Write your answers with two decimal places, rounding if needed. (a) Find - (the mean of the sampling distribution of the sample mean). (b) Find o- (the standard deviation of the sampling distribution of the sample mean). o = |
The population of healthy female adults, the mean red blood cell count (RBC) is 4.8 (millions of cells per cubic millimeter of whole blood). A researcher thinks the RBC is underestimated, so she conducts a test of significance using Null Hypothesis: µ ≤ 4.8 vs. Alternative Hypothesis: µ >4.8. If the true mean RBC is 4.75 and the null hypothesis is rejected, out of the four options below, what has occured? Type 1 Error, Type 2 Error, No error, OR can’t tell without knowing the degrees of freedom?
The yield per tract in a certain region of farmland is known to have a populationstandard deviation of 13 bushels. Using the old seed variety, the population mean yield μwas 39 bushels. A farmer tests a new seed variety on a random sample of 36 tracts, andfinds a sample mean yield of 45.2 bushels. Is the population mean yield using the newseed variety different from 39? Use α= 0.10.a. State the null hypothesis . __________________State the alternative hypothesis.____________________b. Find the test statistic. _____ c. Find the P-value for the test. _____________
For each of the tests, what would be the conclusion if the test were carried out using the α = 0.05 level of significance? H0 : µ = 120, H1:µ ≠ 120, n = 36, S.D of population= 10.3, sample mean = 117.0
A company manufactures tennis balls. When its tennis balls are dropped onto a concrete surface from a height of 100 inches, the company wants the mean height the balls bounce upward to be 54.8 inches. This average is maintained by periodically testing random samples of 25 tennis balls. If the t-value falls between −t0.95 and t0.95, then the company will be satisfied that it is manufacturing acceptable tennis balls. A sample of 25 balls is randomly selected and tested. The mean bounce height of the sample is 56.3 inches and the standard deviation is 0.25 inch. Assume the bounce heights are approximately normally distributed. Is the company making acceptable tennis balls?
Determine the null and alternative hypotheses.In the past, the mean running time for a certain type of radio battery has been 9.6 hours. The manufacterer has introduced a change in the production method and wants to perform a hypothesis test to determine whether the mean running time has changed as a result. Choose the best asnwer below A. H0: μ ≥ 9.6 hoursHA: μ = 9.6 hours B. H0: μ > 9.6hoursHA: μ > 9.6 hours C. H0: μ ≠ 9.6 hoursHA: μ = 9.6hours D. H0: μ = 9.6hoursHA: μ > 9.6 hours E. H0: μ = 9.6 hoursHA: μ ≠ 9.6 hours
54% of students entering four-year colleges receive a degree within six years. Is this percent smaller for students who play intramural sports? 415 of the 800 students who played intramural sports received a degree within six years. What can be concluded at the 0.05 level of significance? H0: p = 0.54 Ha: p [ Select ] ["<", "Not Equal To", ">"] 0.54 p-Value = [ Select ] ["0.03", "0.23", "0.06", "0.11"] [ Select ] ["Fail to Reject Ho", "Reject Ho"] Conclusion: There is [ Select ] ["statistically significant", "insufficient"] evidence to make the conclusion that the population proportion of college students who play intramural sports that receive a degree within six years is less than 0.54. p-Value Interpretation: If the proportion of college students who play intramural sports that receive a degree within six yeas is equal to [ Select ] ["0.52", "0.54", "0.48", "0.50"]and if another study was done with a new randomly selected collection of…
What is the critical value? A. 2.33 B. 2.492 C. 2.575 D. 2.797
Westjet claims that it's avearage time to fly to Toronto from Thunder Bay is 121 minutes. A random sample of 29 flights from Thunder Bay to Toronto were observed and yeilded a mean of 140 minutes. Assuming that o = 3.1 do we have enough evidence to show that the mean flight is more than 121 minutes? Use a = 0.1 and use our tables. Select the correct null and alternative hypotheses: OA. Ho: X= 140,HA: X 121 OF. Ho X = 140,H₁ : X > 140 OG. None of the above Select the type of distribution to be used in this question: OA. Z-distribution B. t-distribution OC. Chi-Square distribution OD. None of the above The rejection region for this test is: OA. (-∞, -1.28) OB. (1.96,∞) OC. (1.645, ∞) OD. (1.28, ∞) OE. (-∞, -1.96) OF. (-∞, -1.645) OG. (-∞, -1.96) U (1.96,∞) OH. (-∞, -1.28) U (1.28,00) OI. (-∞, -1.645) U (1.645, ∞) OJ. None of the above Test statistic = The conclusion for this test is: OA. Fail to Reject Ho OB. Reject Ho OC. Fail to Reject HA OD. Reject HA OE. None of the above
Suppose the national average dollar amount for an automobile insurance claim is $777.86. You work for an agency in Michigan and you are interested in whether or not the state average is less than the national average. The hypotheses for this scenario are as follows: Null Hypothesis: μ ≥ 777.86, Alternative Hypothesis: μ < 777.86. You take a random sample of claims and calculate a p-value of 0.0232 based on the data, what is the appropriate conclusion? Conclude at the 5% level of significance. Question 9 options: 1) The true average claim amount is significantly different from $777.86. 2) The true average claim amount is significantly less than $777.86. 3) The true average claim amount is significantly higher than $777.86. 4) We did not find enough evidence to say the true average claim amount is less than $777.86. 5) The true average claim…
A marketing researcher would like to compare the mean amounts that men and women spend on Christmas gifts. Independent random samples were taken from each group. He would like to conduct a test to determine if women spend more on average. If the null hypothesis is Ho : µM - µf = 0, what is the alternative hypothesis? ge 2: ge 3: OH1 : µM – HF 0 4 OH1 : µM – HF # 0 Page 5: Next Page Dege 10of15