Nine students took the SAT. Their scores are listed below. Later on, they read a book on test preparation and retook the SAT. Their new scores are listed below. Assume that the distribution is normally distributed. 1. Can it be concluded at α = .05 that the scores have changed? Do the hypothesis test. 2. Construct a 95% confidence interval for μd. Student 1 2 3 4 5 6 7 8 9 Before Reading 720 860 850 880 860 710 850 1200 950 After Reading 740 860 840 920 890 720 840 1240 970
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Nine students took the SAT. Their scores are listed below. Later on, they read a book on test preparation and retook the SAT. Their new scores are listed below. Assume that the
1. Can it be concluded at α = .05 that the scores have changed? Do the hypothesis test.
2. Construct a 95% confidence interval for μd.
| Student | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 |
| Before Reading | 720 | 860 | 850 | 880 | 860 | 710 | 850 | 1200 | 950 |
| After Reading | 740 | 860 | 840 | 920 | 890 | 720 | 840 | 1240 | 970 |
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- An Internet retailer would like to investigate the relationship between the amount of time in minutes a purchaser spends on its Web site and the amount of money he or she spends on an order. The table to the right shows the data from a random sample of 12 customers. Construct a 99% confidence interval for the regression slope. Construct a 99% confidence interval for the slope. LCL = and UCL = (Round to three decimal places as needed.) C Time 20 12 28 22 1 13 Order Size $71 $23 $93 $198 $54 $35 Time 5 37 8 37 25 8 Order Size $57 $360 $122 $161 $72 $248A statistics class is estimating the mean height of all female students at their college. They collect a random sample of 42 female students and measure their heights. The mean of the sample is 65.3 inches and the sample standard deviation is 5.4 inches. Find the 90% confidence interval for the mean height of all female students in their school? Assume that the distribution of individual female heights at this school is approximately normal. 1. The t value is 1.3025 2. The standard error has a value of -- 3. The margin of error has a value of 4. Find the 90% confidence interval for the mean height of all female students in their schoolCan you do this problem?
- K A university would like to examine the relationship between a faculty member's performance rating (measured on a scale of 1-20) and his or her annual salary increase. The table to the right shows these data for eight randomly selected faculty members. Construct a 90% confidence interval for the regression slope. Construct a 90% confidence interval for the slope. LCL= and UCL= (Round to three decimal places as needed.) Rating Increase Rating Increase 17 $2400 14 $2000 18 8 22 $2600 14 $2700 $1800 16 $2100 $1600 15 $1900Test whether µ, <µ, at the a = 0.01 level of significance for the sample data shown in the accompanying table. Assume that the populations are normally distributed. Click the icon to view the data table. Determine the null and alternative hypothesis for this test. A. Ho:H1K Large samples of women and men are obtained, and the hemoglobin level is measured in each subject. Here is the 95% confidence interval for the difference between the two population means, where the measures from women correspond to population 1 and the measures from men correspond to population 2: -1.76 g/dLGiven two independent random samples with the following results: n₁ = 16 n₂ = 8 x₁ = 94 X2: $₁ = 16 = 124 $2 = 28 Use this data to find the 90% confidence interval for the true difference between the population means. Assume that the population variances are equal and that the two populations are normally distributed. Copy Data Step 2 of 3: Find the margin of error to be used in constructing the confidence interval. Round your answer to six decimal places.If X=115, σ=22, and n=36, construct a 95% confidence interval estimate of the population mean, μ. Click here to view page 1 of the cumulative standardised normal distribution table. LOADING... Click here to view page 2 of the cumulative standardised normal distribution table. LOADING... The 95% confidence interval is enter your response here≤μ≤enter your response here. (Round to two decimal places as needed.)J1You are interested in finding a 90% confidence interval for the average commute that non-residential students have to their college. The data below show the number of commute miles for 14 randomly selected non-residential college students. Round answers to 3 decimal places where possible. 5 8 11 10 12 19 24 6 26 10 26 10 26 15 a. To compute the confidence interval use a distribution. b. With 90% confidence the population mean commute for non-residential college students is between and miles. c. If many groups of 14 randomly selected non-residential college students are surveyed, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population mean number of commute miles and about percent will not contain the true population mean number of commute miles.Can you please help me with this question?Match to the appropriate answer. You will not use all options and you may not use each option more than once. Dummy variable Coefficient (beta) Correlation coefficient Heteroscedasticity p-value R² + Residual A. Used with categorical variable B. Lower value means statistical significance at a higher confidence level. C. When the distribution of residuals does change as the independent variable changes. D. Higher value means statistical significance at a higher confidence level. E. Difference between the predicted and observed values. F. When the distribution of residuals does not change as the independent variable changes. G. Min=-1, Max=1 H. Min-0, Max=1 1. Used to determine how much dependent variables changes if independent variable changed.SEE MORE QUESTIONSRecommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons Inc
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