Use the Alternating Series Estimation Theorem or Taylor's Inequality to estimate the range of values of x for which the given approximation is accurate to within the stated error. Check your answer graphically. (Enter your answer using interval notation. Round your answers to three decimal places.) cos(x) = 1 2 + (Jerror] <0.00005) 24 Match the differential equation with its direction field. y' = x(8 - y) / / / /// 157 10 /// 22 0.3 -0.2-0.1 - -0.1 - 0.2 0.3. 0.1 0.2 0.3- 0-2 -1 1 2 / / / 0.3 / / 1-Q.3 +021-10.1\ // / // ///// ///// \0.1 02/03/ Q.1 -- 103 x // //// O-2 y 15 10 /// + x -1 0 1 Give reasons for your answer. The slopes at each point are independent of x, so the slopes are the same along each line parallel to the x-axis. Note that for y 8, y' = 0. Oy' = x(8 - y) = 0 on the line y = -x+ and y' -1 on the line y = -x. π Oy' = x(8 - y) = 0 on the lines x = 0 and y = 0, and y' > 0 for 0 < x < . <<²,0

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Use the Alternating Series Estimation Theorem or Taylor's Inequality to estimate the range of values of x for which the given
approximation is accurate to within the stated error. Check your answer graphically. (Enter your answer using interval notation.
Round your answers to three decimal places.)
cos(x) = 1
2
+
(Jerror] <0.00005)
24
Transcribed Image Text:Use the Alternating Series Estimation Theorem or Taylor's Inequality to estimate the range of values of x for which the given approximation is accurate to within the stated error. Check your answer graphically. (Enter your answer using interval notation. Round your answers to three decimal places.) cos(x) = 1 2 + (Jerror] <0.00005) 24
Match the differential equation with its direction field.
y' = x(8 - y)
/ / /
///
157
10
///
22
0.3 -0.2-0.1
-
-0.1
-
0.2 0.3.
0.1
0.2
0.3-
0-2
-1
1
2
/ / /
0.3 / /
1-Q.3 +021-10.1\
// /
//
/////
/////
\0.1
02/03/
Q.1
--
103
x
//
////
O-2
y
15
10
///
+
x
-1
0
1
Give reasons for your answer.
The slopes at each point are independent of x, so the slopes are the same along each line parallel to the x-axis. Note
that for y 8, y' = 0.
Oy' = x(8 - y) = 0 on the line y = -x+ and y' -1 on the line y = -x.
π
Oy' = x(8 - y) = 0 on the lines x = 0 and y = 0, and y' > 0 for 0 < x < .
<<²,0<y<
Oy' = x(8 - y) = 0 on the lines x = 0 and y = 8.
The slopes at each point are independent of y, so the slopes are the same along each line parallel to the y-axis. Note
that for y=8, y' = 0.
Transcribed Image Text:Match the differential equation with its direction field. y' = x(8 - y) / / / /// 157 10 /// 22 0.3 -0.2-0.1 - -0.1 - 0.2 0.3. 0.1 0.2 0.3- 0-2 -1 1 2 / / / 0.3 / / 1-Q.3 +021-10.1\ // / // ///// ///// \0.1 02/03/ Q.1 -- 103 x // //// O-2 y 15 10 /// + x -1 0 1 Give reasons for your answer. The slopes at each point are independent of x, so the slopes are the same along each line parallel to the x-axis. Note that for y 8, y' = 0. Oy' = x(8 - y) = 0 on the line y = -x+ and y' -1 on the line y = -x. π Oy' = x(8 - y) = 0 on the lines x = 0 and y = 0, and y' > 0 for 0 < x < . <<²,0<y< Oy' = x(8 - y) = 0 on the lines x = 0 and y = 8. The slopes at each point are independent of y, so the slopes are the same along each line parallel to the y-axis. Note that for y=8, y' = 0.
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