Find the radius of convergence, R, of the series. Then find the interval, I, of convergence of the series. хл n4gn n = 1 Step 1 We are given the following power series and must determine the radius of convergence, R. 00 Σ n4gn хл n = 1 - - Recall that a power series centered at a is of the form Σ c(x − a)”. The radius of convergence is the positive value R such that the power series converges if |x − a| < R and diverges if |x − a] > R. The given power series is 00 n = 0 centered at хп Let an To begin, find and simplify the limit. be the terms of the given power series. By the Ratio Test, we know the convergence of the power series can be tested with the limit of nAgn an+1 an lim n→ ∞o an + 1 an lim n→ ∞o x7 +1 (n + 1)4 9n+1 xn nAgn = lim n→ ∞ (n + 1)4 = lim 9 noo = 1x ([ 9 n + 1 X × O 4

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.3: Geometric Sequences
Problem 49E
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Find the radius of convergence, R, of the series. Then find the interval, I, of convergence of the series.
хл
n4gn
n = 1
Step 1
We are given the following power series and must determine the radius of convergence, R.
00
Σ n4gn
хл
n = 1
-
-
Recall that a power series centered at a is of the form Σ c(x − a)”. The radius of convergence is the positive value R such that the power series converges if |x − a| < R and diverges if |x − a] > R. The given power series is
00
n = 0
centered at
хп
Let an
To begin, find and simplify the limit.
be the terms of the given power series. By the Ratio Test, we know the convergence of the power series can be tested with the limit of
nAgn
an+1
an
lim
n→ ∞o
an + 1
an
lim
n→ ∞o
x7 +1
(n + 1)4 9n+1
xn
nAgn
= lim
n→ ∞
(n + 1)4
=
lim
9 noo
= 1x ([
9
n + 1
X
× O
4
Transcribed Image Text:Find the radius of convergence, R, of the series. Then find the interval, I, of convergence of the series. хл n4gn n = 1 Step 1 We are given the following power series and must determine the radius of convergence, R. 00 Σ n4gn хл n = 1 - - Recall that a power series centered at a is of the form Σ c(x − a)”. The radius of convergence is the positive value R such that the power series converges if |x − a| < R and diverges if |x − a] > R. The given power series is 00 n = 0 centered at хп Let an To begin, find and simplify the limit. be the terms of the given power series. By the Ratio Test, we know the convergence of the power series can be tested with the limit of nAgn an+1 an lim n→ ∞o an + 1 an lim n→ ∞o x7 +1 (n + 1)4 9n+1 xn nAgn = lim n→ ∞ (n + 1)4 = lim 9 noo = 1x ([ 9 n + 1 X × O 4
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