Help, Please! ### Educational Content: Understanding Standard Normal Curve and Z-Scores**Task Instructions:**Use technology to determine the indicated area under the standard normal curve. Include an accurately labeled sketch of the Normal curve and shade the relevant region.**Tasks:**a. **Find the probability that a z-score will be 1.42 or less.**- The graph labeled "A" depicts a normal distribution curve with the area to the left of the z-score 1.42 shaded in light blue, indicating the cumulative probability for a z-score of 1.42 or less.b. **Find the probability that a z-score will be 1.42 or more.**- The graph labeled "D" shows the area to the right of the z-score 1.42 shaded, representing the probability for a z-score of 1.42 or more.c. **Find the probability that a z-score will be between -1.3 and -1.03.**- The graph labeled "C" illustrates the area between the z-scores -1.3 and -1.03 shaded in blue, which identifies the probability of a z-score falling within this range.**Graph Selection Questions:**1. **The probability that a z-score will be 1.42 or less is:** - (Round to four decimal places as needed.)2. **Which graph below shows the probability that a z-score is 1.42 or more?**- Correct answer: Graph D.Use the graphs to help visualize these probabilities and better understand the distribution of data in a standard normal curve. These visual aids facilitate accurate interpretation of z-scores and their corresponding probabilities.

Name: Help, Please! ### Educational Content: Understanding Standard Normal C
Uploaded: 2024-03-20T07:07:37.000Z
Channel: Bartleby
Description: Help, Please! ### Educational Content: Understanding Standard Normal Curve and Z-Scores**Task Instructions:**Use technology to determine the indicated area under the standard normal curve. Include an accurately labeled sketch of the Normal curve and

a. Probability that a z score will be 1.42 or less: P(z<=1.42)=0.9222, from the excel function, =NORM.DIST(1.42,0,1,TRUE) Correct graph: b) The probability that a z score be 1.42 or more: P(z>=1.42)=1-P(z<1.42) =1-0.9222 from part (a) =0.0778 Correct Graph: c) The probability that a z score will be between -1.3 and -1.03: P-1.3≤z≤-1.03=P(z≤-1.03)-P(z≤-1.3) =0.0547 From the Excel function, =NORM.DIST(-1.03,0,1,TRUE)-NORM.DIST(-1.3,0,1,TRUE) Correct Graph: