Use stoichiometric methods to analyze a mixture.Close ProblemA mixture of MgCl, and inert material is analyzed to determine the Mg content. First the mixture is dissolved in water. Then allof the chloride ion is precipitated as AgCl by the addition of an excess of silver nitrate.MgCl2(aq) + 2A£NO3(aq) 2A£CI(s) + Mg(NO3)½(aq)In one experiment, a 0.5770 g sample of the mixture resulted in 1.3717 g of AgCl. Determine the percent (by mass) of Mg in themixture.% MgCheck & Submit AnswerShow ApproachA huluFEBétv12F10F8

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Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

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Use stoichiometric methods to analyze a mixture.
Close Problem
A mixture of MgCl, and inert material is analyzed to determine the Mg content. First the mixture is dissolved in water. Then all
of the chloride ion is precipitated as AgCl by the addition of an excess of silver nitrate.
MgCl2(aq) + 2A£NO3(aq) 2A£CI(s) + Mg(NO3)½(aq)
In one experiment, a 0.5770 g sample of the mixture resulted in 1.3717 g of AgCl. Determine the percent (by mass) of Mg in the
mixture.
% Mg
Check & Submit Answer
Show Approach
A hulu
FEB
étv
12
F10
F8

Expert Solution

Step 1

$G i v e n : M a s s o f s a m p l e = 0.5770 g m a s s o f A g C l f o r m e d = 1.3717 g a l s o f r o m t a b l e : m o l a r m a s s o f M g C l_{2} = 95.21 g m o l a r m a s s o f A g C l = 143.32 g g i v e n r e a c t i o n : M g C l_{2} + 2 A g N O_{3} \to 2 A g C l + M g (N O_{3}) 1 m o l e o f M g C l_{2} g i v e s 2 m o l e s o f A g C l n o o f m o l e s o f A g C l f o r m e d = \frac{m a s s o f A g C l f o r m e d}{m o l a r m a s s o f A g C l} = \frac{1.3717 g}{143.32 g} = 0.0096 m o l e A s, 1 m o l e o f M g C l_{2} g i v e s 2 m o l e s o f A g C l i . e n o o f m o l e o f M g C l_{2} c o n s u m e d = 1 / 2 t h e n o o f m o l e o f A g C l f o r m e d ∴ n o o f m o l e o f M g C l_{2} u s e d = \frac{1}{2} x 0.0096 m o l e = 0.0048 m o l e$

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