Lead ions can be precipitated from solution with KC1 according to the following reaction: Pb²+ (aq) + 2 KCl(aq) → PbCl₂(s) + 2 K+ (aq) When 28.8 g KCl is added to a solution containing 25.5 g Pb²+, a PbCl₂ precipitate forms. The precipitate is filtered and dried and found to have a mass of 29.6 g. Part A Determine the limiting reactant. KCI Pb²+ Submit Part B m = Determine the theoretical yield of PbCl₂. Submit Part C Request Answer ΨΕ ΑΣΦ Submit Request Answer Determine the percent yield for the reaction. ΨΕ ΑΣΦ Request Answer BE ? ? % g

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Lead ions can be precipitated from solution with KC1
according to the following reaction:
Pb²+ (aq) + 2 KCl(aq) → PbCl₂(s) + 2 K+ (aq)
When 28.8 g KCl is added to a solution containing 25.5 g
Pb²+, a PbCl₂ precipitate forms. The precipitate is
filtered and dried and found to have a mass of 29.6 g.
Part A
Determine the limiting reactant.
KCI
Pb²+
Submit
Part B
m =
Determine the theoretical yield of PbCl₂.
Submit
Part C
Request Answer
ΨΕ ΑΣΦ
Submit
Request Answer
Determine the percent yield for the reaction.
ΨΕ ΑΣΦ
Request Answer
BE
?
?
%
g
Transcribed Image Text:Lead ions can be precipitated from solution with KC1 according to the following reaction: Pb²+ (aq) + 2 KCl(aq) → PbCl₂(s) + 2 K+ (aq) When 28.8 g KCl is added to a solution containing 25.5 g Pb²+, a PbCl₂ precipitate forms. The precipitate is filtered and dried and found to have a mass of 29.6 g. Part A Determine the limiting reactant. KCI Pb²+ Submit Part B m = Determine the theoretical yield of PbCl₂. Submit Part C Request Answer ΨΕ ΑΣΦ Submit Request Answer Determine the percent yield for the reaction. ΨΕ ΑΣΦ Request Answer BE ? ? % g
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