Use ray diagrams and the mirror equation to locate the position, orientation, and type of image of an object placed front of a convex mirror focal length -20 cm. Submit Request Answer Part D The object distance is 44 cm; find the magnification (positive for upright image and negative for inverted image). m = Submit Part E Submit Part F ΠΑΣΦ The object distance is 14cm; find the distance from the image to the mirror (positive for real image and negative for virtual image). Express your answer with the appropriate units. m = Request Answer HA 3 Value 1 Request Answer Units VE ΑΣΦ 3 ? ? The object distance is 14 cm; find the magnification (positive for upright image and negative for inverted image).
Ray Optics
Optics is the study of light in the field of physics. It refers to the study and properties of light. Optical phenomena can be classified into three categories: ray optics, wave optics, and quantum optics. Geometrical optics, also known as ray optics, is an optics model that explains light propagation using rays. In an optical device, a ray is a direction along which light energy is transmitted from one point to another. Geometric optics assumes that waves (rays) move in straight lines before they reach a surface. When a ray collides with a surface, it can bounce back (reflect) or bend (refract), but it continues in a straight line. The laws of reflection and refraction are the fundamental laws of geometrical optics. Light is an electromagnetic wave with a wavelength that falls within the visible spectrum.
Converging Lens
Converging lens, also known as a convex lens, is thinner at the upper and lower edges and thicker at the center. The edges are curved outwards. This lens can converge a beam of parallel rays of light that is coming from outside and focus it on a point on the other side of the lens.
Plano-Convex Lens
To understand the topic well we will first break down the name of the topic, ‘Plano Convex lens’ into three separate words and look at them individually.
Lateral Magnification
In very simple terms, the same object can be viewed in enlarged versions of itself, which we call magnification. To rephrase, magnification is the ability to enlarge the image of an object without physically altering its dimensions and structure. This process is mainly done to get an even more detailed view of the object by scaling up the image. A lot of daily life examples for this can be the use of magnifying glasses, projectors, and microscopes in laboratories. This plays a vital role in the fields of research and development and to some extent even our daily lives; our daily activity of magnifying images and texts on our mobile screen for a better look is nothing other than magnification.
![**Assignment: Mirror Equation and Image Characteristics**
**Objective:**
Use ray diagrams and the mirror equation to determine the position, orientation, and type of image for an object placed in front of a convex mirror with a focal length of -20 cm.
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**Part D**
- **Task:** The object distance is 44 cm. Calculate the magnification (positive for upright images and negative for inverted images).
- **Input Box for Answer:**
\[ m = \]
- **Submit Button**
- **Request Answer Button**
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**Part E**
- **Task:** The object distance is 14 cm. Find the distance from the image to the mirror (positive for real image and negative for virtual image). Express your answer with the appropriate units.
- **Input Box for Answer:**
\[ s' = \]
**Value | Units**
- **Submit Button**
- **Request Answer Button**
---
**Part F**
- **Task:** The object distance is 14 cm. Calculate the magnification (positive for upright images and negative for inverted images).
- **Input Box for Answer:**
\[ m = \]
- **Submit Button**
- **Request Answer Button**
---
**Notes:**
- Ensure accurate use of the mirror equation: \(\frac{1}{f} = \frac{1}{s} + \frac{1}{s'}\)
- Understand the sign convention: In convex mirrors, focal length (f) is negative.
- Magnification (m) is given by the equation: \(m = -\frac{s'}{s}\)
For further assistance, refer to example problems and diagrams provided in the course materials.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F34828ee0-4ec4-4963-9794-d063709fbf61%2F9f7c53da-4bc6-45b5-8d86-c6590e9ca756%2Fjgz3sgx_processed.jpeg&w=3840&q=75)
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