Answer in Bold Please **Transcription and Explanation for Educational Content**---**Topic:** Mirror and Image Analysis**Scenario:**Object \( O \) is positioned on the central axis of a spherical or plane mirror.**Table Definitions:**- \( f \) refers to the focal distance.- \( p \) indicates the object distance.- \( i \) denotes the image distance.- \( m \) stands for the lateral magnification.**Task:** Fill in the missing information, including sign conventions.**Given Table Values:**| \( f \) (cm) | \( p \) (cm) | \( i \) (cm) | \( m \) ||--------------|--------------|--------------|-----------|| 30 | | | 0.12 |**Checklist: Describe the mirror and image.** (Select all that apply.)- [ ] plane mirror- [ ] concave mirror- [ ] convex mirror- [ ] real image- [ ] virtual image- [ ] upright image- [ ] inverted image- [ ] image on same side of mirror as \( O \)- [ ] image on opposite side of mirror as \( O \)**Instructions for Completing the Activity:**1. **Determine Object and Image Placement:** - Calculate the object distance \( p \) and image distance \( i \) using the mirror formula and provided magnification. 2. **Assess Mirror Type:** - Utilize the given focal length to ascertain whether the mirror is concave or convex.3. **Identify Image Characteristics:** - Use the magnification value to determine if the image is upright or inverted.4. **Correctly Classify the Image:** - Based on calculations, select the correct real or virtual, and side of placement classifications.This exercise demonstrates the principles of optics and mirror reflections, allowing students to explore and understand the relationships between focal length, object distance, image distance, and magnification.

Given f=30cm And magnification m=0.12 since the magnification is not equal to 1 therefore it cannot…

Answered: Object O stands on the central axis of…

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