Use latest NSCP/NSCP 2015 formula to solve this problem *Use hand written to solve this problem *Kindly refer my picture attached presented formula for block shear . The butt connection shows 8-22 mm dia. A325 bolts spaced as follows: S1 = 40 mm S3 = 50 mm t1 = 16 mm S2 = 80 mm S4 = 100 mm t2 = 12 mm Steel strength and stresses are: Fy = 248 MPa Fu = 400 MPa Allowable tensile stress on the gross area = 148 MPa Allowable tensile stress on the net area = 200 MPa Allowable shear stress on the net area = 120 MPa Allowable bolt shear stress, Fv = 120 MPa Bolt Hole diameter = 25 mm Questions: A. Based on block shear strength
Use latest NSCP/NSCP 2015 formula to solve this problem *Use hand written to solve this problem *Kindly refer my picture attached presented formula for block shear . The butt connection shows 8-22 mm dia. A325 bolts spaced as follows: S1 = 40 mm S3 = 50 mm t1 = 16 mm S2 = 80 mm S4 = 100 mm t2 = 12 mm Steel strength and stresses are: Fy = 248 MPa Fu = 400 MPa Allowable tensile stress on the gross area = 148 MPa Allowable tensile stress on the net area = 200 MPa Allowable shear stress on the net area = 120 MPa Allowable bolt shear stress, Fv = 120 MPa Bolt Hole diameter = 25 mm Questions: A. Based on block shear strength
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
Topic:Bolted Steel Connection - Civil Engineering
*Use latest NSCP/NSCP 2015 formula to solve this problem
*Use hand written to solve this problem
*Kindly refer my picture attached presented formula for block shear .
The butt connection shows 8-22 mm dia. A325 bolts spaced as follows:
S1 = 40 mm S3 = 50 mm t1 = 16 mm
S2 = 80 mm S4 = 100 mm t2 = 12 mm
Steel strength and stresses are:
Fy = 248 MPa Fu = 400 MPa
Allowable tensile stress on the gross area = 148 MPa
Allowable tensile stress on the net area = 200 MPa
Allowable shear stress on the net area = 120 MPa
Allowable bolt shear stress, Fv = 120 MPa
Bolt Hole diameter = 25 mm
Questions:
A. Based on block shear strength
Transcribed Image Text:R₁ = 0.6FuAnv + Ups FuAnt ≤ 0.6FyAgv + Ubs FuAnt
kindly, use this formula
p=0.75(LRFD)
where
Agu
Ant
Anv
n = 2.00 (ASD)
gross area subject to shear, mm²
net area subject to tension, mm²
net area subject to shear, mm²
Where the tension stress is uniform, Ubs = 1; where the
tension stress is nonuniform, Ubs = 0.5.
Transcribed Image Text:t1
T
#
Iss
S3 S4 S3
#
53 54 53
t2
t2
→T
S1
S2
S1
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