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Use Integration by Parts to find 2x tan-¹(x) dx. df O r² (tan(x)) — 2(tan-'(x)) +C O r² (tan-¹) + (tan-¹(x² + 1)) — 2-C O r² (tan-¹(x)) — 2(tan-(x)) -C O None of these. ² (tan-¹(x)) + (tan-¹(x)) - x + C

Use Integration by Parts to find 2x tan-¹(x) dx. df O r² (tan(x)) — 2(tan-'(x)) +C O r² (tan-¹) + (tan-¹(x² + 1)) — 2-C O r² (tan-¹(x)) — 2(tan-(x)) -C O None of these. ² (tan-¹(x)) + (tan-¹(x)) - x + C

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Use Integration by Parts to find [22 2x tan-¹(x) dx. O r² (tan¹(x)) = x(tan−¹(x)) + C O x² (tan-¹2) + (tan¯'(x² + 1)) − x +C O r² (tan-¹(x)) — 2(tan-¹(x)) - C None of these. O ² (tan-¹(x)) + (tan¯¹(x)) = x + C
Transcribed Image Text:Use Integration by Parts to find [22 2x tan-¹(x) dx. O r² (tan¹(x)) = x(tan−¹(x)) + C O x² (tan-¹2) + (tan¯'(x² + 1)) − x +C O r² (tan-¹(x)) — 2(tan-¹(x)) - C None of these. O ² (tan-¹(x)) + (tan¯¹(x)) = x + C
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