Use image below You’re not solving anything for this question just drawing ! No math is required so do not write any equations! Draw the Free body diagram of the beam using the figure below
Use image below You’re not solving anything for this question just drawing ! No math is required so do not write any equations! Draw the Free body diagram of the beam using the figure below
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Use image below
You’re not solving anything for this question just drawing ! No math is required so do not write any equations!
Draw the Free body diagram of the beam using the figure below
![**Analysis of the Beam Under Uniformly Distributed Load**
**Diagram Description:**
The diagram above illustrates a simply supported beam under a uniformly distributed load. The beam is inclined at an angle and is supported at two points: a fixed support at point B and a pin support at point A.
- **Point A:** The pin support is located 1 meter from the left end of the beam.
- **Point B:** The fixed support is located at the right end of the beam.
- **Load Distribution:** The load is uniformly distributed along the length of the beam with a magnitude of 800 N/m.
- **Beam Dimensions:**
- The total length from the pin support at point A to the fixed support at point B is 4 meters.
- The vertical distance from the left end of the beam to the horizontal ground line is 3 meters.
- The horizontal distance between the left end of the beam and point A is 1 meter (pin support is located 1 meter horizontally from the left end).
- The horizontal distance from point A to point B (fixed support) is 3 meters.
**Uniformly Distributed Load Calculation:**
The uniformly distributed load of 800 N/m is acting downward along the entire length of the beam. This type of loading typically results in both shear forces and bending moments that need to be analyzed to ensure the structural integrity of the beam.
**Force and Moment Calculations:**
To calculate the reactions at the supports and the internal stresses, you would typically:
1. **Calculate the total load:**
- **Total Load (W):** The total load can be found by multiplying the load per unit length (800 N/m) by the length of the beam (4 m):
\[
W = 800 \text{ N/m} \times 4 \text{ m} = 3200 \text{ N}
\]
2. **Determine the reactions at the supports:**
- Use static equilibrium equations:
\[
\sum F_y = 0, \quad \sum M_A = 0, \quad \sum M_B = 0
\]
- Where \( F_y \) represents vertical force equilibrium, and \( M_A \) and \( M_B \) are the moments about supports A and B respectively.
By solving these equations, you can find the reactions at the supports and the internal shear forces and moments along the beam.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fed59431e-03fe-4a4d-a12d-387ad46dfe48%2Fbd812d8a-80de-4926-9843-8f4e70f47dd3%2Fxe5scyd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Analysis of the Beam Under Uniformly Distributed Load**
**Diagram Description:**
The diagram above illustrates a simply supported beam under a uniformly distributed load. The beam is inclined at an angle and is supported at two points: a fixed support at point B and a pin support at point A.
- **Point A:** The pin support is located 1 meter from the left end of the beam.
- **Point B:** The fixed support is located at the right end of the beam.
- **Load Distribution:** The load is uniformly distributed along the length of the beam with a magnitude of 800 N/m.
- **Beam Dimensions:**
- The total length from the pin support at point A to the fixed support at point B is 4 meters.
- The vertical distance from the left end of the beam to the horizontal ground line is 3 meters.
- The horizontal distance between the left end of the beam and point A is 1 meter (pin support is located 1 meter horizontally from the left end).
- The horizontal distance from point A to point B (fixed support) is 3 meters.
**Uniformly Distributed Load Calculation:**
The uniformly distributed load of 800 N/m is acting downward along the entire length of the beam. This type of loading typically results in both shear forces and bending moments that need to be analyzed to ensure the structural integrity of the beam.
**Force and Moment Calculations:**
To calculate the reactions at the supports and the internal stresses, you would typically:
1. **Calculate the total load:**
- **Total Load (W):** The total load can be found by multiplying the load per unit length (800 N/m) by the length of the beam (4 m):
\[
W = 800 \text{ N/m} \times 4 \text{ m} = 3200 \text{ N}
\]
2. **Determine the reactions at the supports:**
- Use static equilibrium equations:
\[
\sum F_y = 0, \quad \sum M_A = 0, \quad \sum M_B = 0
\]
- Where \( F_y \) represents vertical force equilibrium, and \( M_A \) and \( M_B \) are the moments about supports A and B respectively.
By solving these equations, you can find the reactions at the supports and the internal shear forces and moments along the beam.
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