Problem 6: Values: A = 13 lb 0₁ = 20° 0₂ = 60° Use the figure shown on the right to complete the following steps: a) Express the force as a Cartesian vector. Use basic trig functions to determine the force components. Some textbooks provide equations for this, but it's a waste of time to memorize these, or worse, to apply them without understanding what you're doing. Just break the vector into two right triangles and apply basic trig. Nothing to memorize. Nothing fancy. The leg of one triangle becomes the hypotenuse of the other. b) Specify the coordinate direction angles of the vector. These are referred to in Hibbeler's textbook as a, b, and y. They are also sometimes referred to as 0, 0, and 0-. See the figure below for clarification. Use vector equations for this, not trig. That is, once you have the vector components, this is a straightforward calc- no crazy trig or geometry involved. Ai AkA Y B Ayj -y N 0₂ 0₁ A y

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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Problem 6:
Values:
A = 13 lb
0₁ = 20⁰
0₂ = 60°
Use the figure shown on the right to complete the following steps:
a) Express the force as a Cartesian vector. Use basic trig functions to
determine the force components. Some textbooks provide equations
for this, but it's a waste of time to memorize these, or worse, to apply
them without understanding what you're doing. Just break the vector
into two right triangles and apply basic trig. Nothing to memorize.
Nothing fancy. The leg of one triangle becomes the hypotenuse of the
other.
b) Specify the coordinate direction angles of the vector. These
are referred to in Hibbeler's textbook as a, ß, and y. They
are also sometimes referred to as 0, 0y, and 0-. See the
figure below for clarification. Use vector equations for this,
not trig. That is, once you have the vector components, this
is a straightforward calc- no crazy trig or geometry
involved.
X
Ai
Z
A.KA
UA
Y
B
A,j
-y
N
0₂
0₁
A
y
Transcribed Image Text:Problem 6: Values: A = 13 lb 0₁ = 20⁰ 0₂ = 60° Use the figure shown on the right to complete the following steps: a) Express the force as a Cartesian vector. Use basic trig functions to determine the force components. Some textbooks provide equations for this, but it's a waste of time to memorize these, or worse, to apply them without understanding what you're doing. Just break the vector into two right triangles and apply basic trig. Nothing to memorize. Nothing fancy. The leg of one triangle becomes the hypotenuse of the other. b) Specify the coordinate direction angles of the vector. These are referred to in Hibbeler's textbook as a, ß, and y. They are also sometimes referred to as 0, 0y, and 0-. See the figure below for clarification. Use vector equations for this, not trig. That is, once you have the vector components, this is a straightforward calc- no crazy trig or geometry involved. X Ai Z A.KA UA Y B A,j -y N 0₂ 0₁ A y
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