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Consider the system shown in FIGURE P3-44 of the textbook. The designer has made several changes to the system. These changes are: • the load of 6 kN/m has been changed to 11 kN/m, • the central length of 2 m has been changed to 4 m o this means the load is applied over the beam from 1 m to the right of point 'A' T0 point 'C'. What is the magnitude of the resultant of the distributed load? 5 kN 55 kN 0.513 kN 93.6 kN 11 kN 12.1 kN 91.4 kN O kN

Consider the system shown in FIGURE P3-44 of the textbook. The designer has made several changes to the system. These changes are: • the load of 6 kN/m has been changed to 11 kN/m, • the central length of 2 m has been changed to 4 m o this means the load is applied over the beam from 1 m to the right of point 'A' T0 point 'C'. What is the magnitude of the resultant of the distributed load? 5 kN 55 kN 0.513 kN 93.6 kN 11 kN 12.1 kN 91.4 kN O kN

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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**Figure P3-44** This diagram illustrates a beam subjected to a uniformly distributed load of 6 kN/m. The beam is supported at two points: a fixed support at point A and a roller support at point B. The following details describe the geometry and loading of the beam: - The beam is horizontal and extends from point A on the left to point C on the right. - Point A is a fixed support, depicted with a triangular set of lines indicating a fixed end. - Point B is located 1 meter from point A and is represented by a circle, describing a roller support that allows vertical movement. - Point C is at the right end, 1 meter from point B. - The distributed load of 6 kN/m spans the length from point B to point C, indicated by arrows pointing downward along the beam between these points. - The total span of the beam from A to C is 2 meters. This setup is typically analyzed to determine the reactions at the supports and the bending moments and shear forces along the beam.
Transcribed Image Text:**Figure P3-44** This diagram illustrates a beam subjected to a uniformly distributed load of 6 kN/m. The beam is supported at two points: a fixed support at point A and a roller support at point B. The following details describe the geometry and loading of the beam: - The beam is horizontal and extends from point A on the left to point C on the right. - Point A is a fixed support, depicted with a triangular set of lines indicating a fixed end. - Point B is located 1 meter from point A and is represented by a circle, describing a roller support that allows vertical movement. - Point C is at the right end, 1 meter from point B. - The distributed load of 6 kN/m spans the length from point B to point C, indicated by arrows pointing downward along the beam between these points. - The total span of the beam from A to C is 2 meters. This setup is typically analyzed to determine the reactions at the supports and the bending moments and shear forces along the beam.
**Problem Description:** Consider the system shown in FIGURE P3-44 of the textbook. The designer has made several changes to the system. These changes are: - The load of 6 kN/m has been changed to 11 kN/m. - The central length of 2 m has been changed to 4 m. - This means the load is applied over the beam from 1 m to the right of point 'A' to point 'C'. **Question:** What is the magnitude of the *resultant* of the distributed load? **Answer Choices:** - ○ 5 kN - ○ 55 kN - ○ 0.513 kN - ○ 93.6 kN - ○ 11 kN - ○ 12.1 kN - ○ 91.4 kN - ○ 0 kN **Explanation:** The problem involves calculating the resultant force of a distributed load applied over a specific section of a beam. The changes in the load's magnitude and the section of the beam it covers must be considered to determine the resultant.
Transcribed Image Text:**Problem Description:** Consider the system shown in FIGURE P3-44 of the textbook. The designer has made several changes to the system. These changes are: - The load of 6 kN/m has been changed to 11 kN/m. - The central length of 2 m has been changed to 4 m. - This means the load is applied over the beam from 1 m to the right of point 'A' to point 'C'. **Question:** What is the magnitude of the *resultant* of the distributed load? **Answer Choices:** - ○ 5 kN - ○ 55 kN - ○ 0.513 kN - ○ 93.6 kN - ○ 11 kN - ○ 12.1 kN - ○ 91.4 kN - ○ 0 kN **Explanation:** The problem involves calculating the resultant force of a distributed load applied over a specific section of a beam. The changes in the load's magnitude and the section of the beam it covers must be considered to determine the resultant.
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