Second moment of areaThe second moment of area employed in the equation to calculate maximumshear stress can be calculated as(units : mm)Iz ==First moment of areaThe first moment of area employed in the equation to calculate maximum shearstress can be calculated as(units : mm³)S = A cross-section of a beam is shown in Figure Q2. If the shear force in this section isV 163 KN, determine the value and the location of the maximum shear stress inthe section.In Figure Q2, a = 77 mm and the origin of the coordinate system is at centroid ofthe cross section.y=AZ=amm;2amm;O4aThe vertical coordinate (y-coordinate; the y-axis serves as the axis of symmetryof the cross-section.) and horizontal coordinate (z-coordinate) of the locationwhere the maximum shear stress occurs in the section areFigure Q23aaThe vertical distance from the location where the maximum shear stress occurs inthe section to the bottom side (AB) of the cross section can be calculated asDistance =mm

Given : The shear force in this section is The diagram is,

Second moment of area The second moment of area employed in the equation to calculate maximum shear stress can be calculated as Iz = (units : mm) First moment of area The first moment of area employed in the equation to calculate maximum shear stress can be calculated as (units : mm³) S =

Second moment of area The second moment of area employed in the equation to calculate maximum shear stress can be calculated as Iz = (units : mm) First moment of area The first moment of area employed in the equation to calculate maximum shear stress can be calculated as (units : mm³) S =

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Please write the final answer with unit 3.Length and diameter of a bearing are equal (d=L). This bearing should be able to withstand the allowable support force of 80 N. Allowable support tension is 20 N/cm?. Determine the length of bearing.
The person who answered this previously used sin and cos-please use geometry for example 3,4,5 triangles things of that nature. Thanks
Question 6 - SFD & BMD-Simply Beam (Point) From the beam shown below, i) Draw the Free Body Diagram (FBD) & Find R1 & R2 ii) Draw Shear Force Diagram (SFD), clearly show all the shear force the beam is experiencing at each point. iii) Draw the Bending Moment Diagram (BMD), clearly show all the bending moment the beam is experiencing at each point. 400 N 600 N 200 N 800 N 0.8 m 0.3 m--0.3 m- 0.4 m 0.4 m C 0.9 m 0.5 mo.2 m-
For the beam shown, find the reactions at the supports and plot the shear-force and bending-moment diagrams. = 450 lbf, V2 = 35 lbf/in, V3 = 12 in, and V4 = 4 in. v3 A v1 v4 B Provide values at all key points shown in the given shear-force and bending-moment diagrams. A SITIVE FIVE d v4 Shear Diagram v2 D 0.00 3x in.) P R 0.00
Mechanical engineering
b) A 1.25 m long cable has a diameter 3.50 mm with a Young's Modulus, E, of 9.75 x 10⁹ N/m². When the wire is placed under tension, it experiences a stress of 202.52 x 106 N/m², the length of the cable extends by 36.35 mm. Calculate the force that the cable experiences under tension and the strain energy density (U/V) due to deformation. Give your answers in newtons (N) to 2 decimal places for the force; and in joules per cubic metre (J/m³) for the strain energy density to 2 decimal places. Assume the cable is solid and the material is homogeneous. c) Figure Q1c shows a bracket on rollers that allow the bracket to move along a beam in the horizontal direction. A force F₁ of 2625 N acts at point A where the angle between F, and the x-axis is 100. If force F₂ acts at an angle a = 400 between F2 and the y-axis: (i) Determine the magnitude of F2 necessary to maintain bracket on horizontal equilibrium. (ii) Determine the vertical force at A acting along the y-axis. Give your answers to the…
2. Figure (a) shows the cross section of a column that uses a structural shape known as W8 x 67 (wide-flange beam, nominally 8 in. deep, weighing 67 Ib/ft). The American Institute of Steel Construction Structural Steel Handbook lists the following cross-sectional properties: A=19.7 in², Ix =272 in“, and ly =88.6 in4. Figure (b) shows the cross-sectional dimensions for the structural steel section known as C10 x 20 (channel with a nominal depth of 10 in., weighing 20 Ib/ft). The American Institute of Steel Construction Structural Steel Handbook lists the following properties for the cross section: A=5.88 in?, Ix =78.9 inª, and ly =2.81 in*. If a W8 x 67 section is joined to a C10 × 20 section to form a structural member that has the cross section shown in Figure (c), a. Locate the centroid of the built-up section in the Figure (c). b. Calculate the centroidal moments of inertia, Ix and ly for this cross section. 事士 0.606 in. 0.933 in. y Web in. --0.575 in. 10 in. - Flange -- 0.379in.…
When a beam section is subjected to a shear load, a shear stress distribution is developed on the section. The distribution of the shear stress is not linear. Elasticity theory can be used to calculate the shear stress at any point. However, a simpler method can be used to calculate the average shear stress across the width of the section, a distance y above or below the neutral axis. The average VQ shear stress is given by T = Here V is the shear It force on the section, I is the moment of inertia of the entire section about the neutral axis, and t is the width of the section at the distance y where the shear stress is being calculated. Q is the product of the area of the section above (or below) y and the distance from the neutral axis to the centroid of that area (Figure 1). In short, Q is the moment of the area about the neutral axis. I Figure 1 of 1 An I-beam has a flange width b = 250 mm, height h = 250 mm, web thickness tw = 9 mm, and flange thickness tf = 14 mm. Use the…
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