why the expert here wrote -200 cos 75 when Σ Fx = 0 , I understand all steps but how he got - 200 cos 75 ( for the force ) (how the angle is 75 ) can you please clarify for me this point please ...... because I did not got the angle 75 dgree for 200 N force can you draw a diagrm for me please to see how 75 dgree links to 200 N Solution:-D250mmAyBy75°A75°F= 200N1o0mm1oommBxByForMem berA B= O%3D- 200 coS 75 + Ax -Bx=0An - Bn =51.7638EFy = 0%3D- 200-to Sin 75 + Ay + By = 0Ay + By= 193.18522)E MA = O200X 25S0Bx x J00 Sin 75 + By x 100 coS 75 = o%3DBx Sin 75 + By cos75500ForMem beoB CE Fn= 0Bx - N = o >Bx = N2 Fy = 0R- By = oBy = R -OEMc = 0- Bx x loo &n75 + By x 100 cos 7 5=0Bx Sin75 - By x cos 75

As one of the angle is already given as 75°

Answered: why the expert here wrote -200 cos 75…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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why the expert here wrote -200 cos 75 when Σ Fx = 0 , I understand all steps but how he got - 200 cos 75 ( for the force ) (how the angle is 75 ) can you please clarify for me this point please ......

because I did not got the angle 75 dgree for 200 N force can you draw a diagrm for me please to see how 75 dgree links to 200 N

Solution:-
D
250mm
Ay
By
75°
A
75°
F= 200N
1o0mm
1oomm
Bx
By
For
Mem ber
A B
= O
%3D
- 200 coS 75 + Ax -Bx=0
An - Bn =
51.7638
EFy = 0
%3D
- 200-to Sin 75 + Ay + By = 0
Ay + By
= 193.1852
2)
E MA = O
200X 25S0
Bx x J00 Sin 75 + By x 100 coS 75 = o
%3D
Bx Sin 75 + By cos75
500
For
Mem beo
B C
E Fn= 0
Bx - N = o >
Bx = N
2 Fy = 0
R- By = o
By = R -O
EMc = 0
- Bx x loo &n75 + By x 100 cos 7 5=0
Bx Sin75 - By x cos 75

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