Use compounds D and E shown below to answer this question. What would be the observed rotation of a 4: mixture of D:E if pure compound E has a specific rotation of +12°? Show how you arrived at your answer. (Use the back if necessary) CI Br Br. CI compound D compound E
Use compounds D and E shown below to answer this question. What would be the observed rotation of a 4: mixture of D:E if pure compound E has a specific rotation of +12°? Show how you arrived at your answer. (Use the back if necessary) CI Br Br. CI compound D compound E
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Optical Rotation Question**
**Example Question:**
Use compounds D and E shown below to answer this question. What would be the observed rotation of a 4:1 mixture of D:E if pure compound E has a specific rotation of +12°? Show how you arrived at your answer. (Use the back if necessary)
**Diagrams:**
- **Compound D:**
- Structure: Features a chlorine (Cl) atom and a bromine (Br) atom.
- **Compound E:**
- Structure: Features a bromine (Br) atom and a chlorine (Cl) atom.
**Explanation:**
To find the observed rotation of a 4:1 mixture of D:E, use the formula for calculating optical rotation of mixtures:
\[ \text{Observed Rotation} = \left( \frac{4}{5} \right)(\text{Rotation of D}) + \left( \frac{1}{5} \right)(\text{Rotation of E}) \]
- Given that pure compound E has a specific rotation of +12° and assuming compound D has a rotation of -12° due to its enantiomeric nature (opposite sign), the observed rotation is calculated as follows:
\[ \text{Observed Rotation} = \left( \frac{4}{5} \right)(-12°) + \left( \frac{1}{5} \right)(+12°) \]
Calculate each part:
- Compound D contribution: \( \left( \frac{4}{5} \right)(-12°) = -9.6° \)
- Compound E contribution: \( \left( \frac{1}{5} \right)(+12°) = +2.4° \)
Add these contributions:
\[ \text{Observed Rotation} = -9.6° + 2.4° = -7.2° \]
Therefore, the observed rotation of the 4:1 mixture of D:E would be -7.2°.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe05b1731-adb9-4e64-86f3-2af0aa2c396e%2F19f791ff-53d6-4243-992d-b505fe31f6dd%2F6jf2qw_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Optical Rotation Question**
**Example Question:**
Use compounds D and E shown below to answer this question. What would be the observed rotation of a 4:1 mixture of D:E if pure compound E has a specific rotation of +12°? Show how you arrived at your answer. (Use the back if necessary)
**Diagrams:**
- **Compound D:**
- Structure: Features a chlorine (Cl) atom and a bromine (Br) atom.
- **Compound E:**
- Structure: Features a bromine (Br) atom and a chlorine (Cl) atom.
**Explanation:**
To find the observed rotation of a 4:1 mixture of D:E, use the formula for calculating optical rotation of mixtures:
\[ \text{Observed Rotation} = \left( \frac{4}{5} \right)(\text{Rotation of D}) + \left( \frac{1}{5} \right)(\text{Rotation of E}) \]
- Given that pure compound E has a specific rotation of +12° and assuming compound D has a rotation of -12° due to its enantiomeric nature (opposite sign), the observed rotation is calculated as follows:
\[ \text{Observed Rotation} = \left( \frac{4}{5} \right)(-12°) + \left( \frac{1}{5} \right)(+12°) \]
Calculate each part:
- Compound D contribution: \( \left( \frac{4}{5} \right)(-12°) = -9.6° \)
- Compound E contribution: \( \left( \frac{1}{5} \right)(+12°) = +2.4° \)
Add these contributions:
\[ \text{Observed Rotation} = -9.6° + 2.4° = -7.2° \]
Therefore, the observed rotation of the 4:1 mixture of D:E would be -7.2°.
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