Use a t-distribution and the given matched pair sample results to complete the test of the given hypotheses. Assume the results come from random samples, and if the sample sizes are small, assume the underlying distribution of the differences is relatively normal. Assume that differences are computed using d = x1 – x2. Test Ho : Ha = 0 vs Ha : Ha # 0 using the paired difference sample results d = 13.33, sa = 13.6, ng = 25. Give the test statistic and the p-value. Round your answer for the test statistic to two decimal places and your answer for the p-value to three decimal places. test statistic = i p-value = i eTextbook and Media Give the conclusion using a 5 % significance level. O Reject Ho. O Do not reject Ho.
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- The amount of chlorine in 100 cm3 water taken from a water tank was measured, the average was 2.15 mg was found. The expert claims that the amount of chlorine in the water is greater than that measured. For this reason, 100 households were randomly selected, with an average chlorine content of 2.55mg and a variance of 0.49 mg. According to this data, find the account value z. 13 - O A) 8,15 O B) 5,71 O C) -5,71 O D) -8, 15 O E) 0.54Consider a sample data with x=25 and s=2. Compute a chebyshev’s interval for which at least 89% of the data will lie?A researcher takes sample temperatures in Fahrenheit of 16 days from Miami and 14 days from Atlanta. Use the sample data shown in the table. Test the claim that the mean temperature in Miami greater than the mean temperature in Atlanta. Use a significance level of α=0.10α=0.10.Assume the populations are approximately normally distributed with unequal variances.Note that list 1 is longer than list 2, so these are 2 independent samples, not matched pairs. Miami Atlanta 68.3 73.6 83.1 69.3 79.1 54.9 72 81.1 72.8 78.6 83.3 54 82.7 36.1 80.7 44.3 87 58.4 83.1 50.8 77.4 60.5 86.1 61.2 76.3 46.8 74.5 54.4 83.3 78.5 The Null Hypotheses is: H0: μ1 - μ2 = 0 What is the alterative hypothesis? Select the correct symbols for each space. (Note this may view better in full screen mode.)HA: μ1 - μ2 Based on these hypotheses, find the following. Round answers to 4 decimal places. Test Statistic = p-value = The p-value is The correct…
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Make sure you identify all values. An Exercise Science instructor at IVC was interested in comparing the resting pulse rates of students who exercise regularly and the pulse rates of those who de not exercise regularly. Independent simple random samples of 16 students who do not exercise regularly and 12 students who exercise regularly were selected and the resting pulse rates (in beats per minute) were recorded. The summary statistics are presented in the table below. Is there compelling statistical evidence that the mean resting pulse rate of people who do not exercise regularly is greater than the mean resting pulse rate of people who exercise regularly? Use a significance value of 0.05. Two-Sample T-Test Sample…A sample mean is 94, sample size is 27, and population standard deviation is 14 are given. Ho: p=89, Hl: μ#89 and a significance level is 0.10. Use the P-value approach to test the hypothesis. O a z=186; P-value = 0.0314; reject null hypothesis O b. z 186, P-value = 0.0628; reject null hypothesis O c. z=0.36; P-value = 0.7188, do not reject null hypothesis Od. z=0.36, P-value = 0.3594; do not reject null hypothesisA study was done using a treatment group and a placebo group. The results are shown in the table. Assume that the two samples are independent simple random H samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.01 significance level for both parts. a. Test the claim that the two samples are from populations with the same mean. What are the null and alternative hypotheses? OA. Ho: #₁ = 1₂ H₁: H₁ H₂ OC. Ho: H₁Suppose data is collected to predict y from x. If the size of Sample ✓ Calculate the p-value if the test statistic is t = -1.38In a hypothesis test for the population variance, the alternate hypothesis is the population variance doesn't equal 17.0. The significance level to be used is 0.05 and the sample size to be taken is 25. The table value(s) to use from the chi-square distribution is/are 12.401 and 39.364. 13.181 39.364 40.671Identify the IV and the scale of measurement; Identify the DV and the scale of measurement and for the IV – identify the number of levels; Identify null and alternative hypotheses, are they directional or non-directional? Assume that the distributions of the populations are approximately normal.A random sample of vehicle speeds were collected. Use the data to test the claim that the mean vehicle speed is more than 40 mph. Use a 0.05 level of significance. Sample data: x¯=42 mphs=7 mphn=34 Identify the tail of the test. Find the P-value Will the null hypothesis be rejected? Is the initial claim supported?A data set includes weights of garbage discarded in one week from 62 different households. The paired weights of paper and glass were used to obtain the results shown to the right. Is there sufficient evidence to support the claim that there is a linear correlation between weights of discarded paper and glass? Use a significance level of α = 0.05. Click here to view a table of critical values for the correlation coefficient. Determine the null and alternative hypotheses. Ho: P H₁: p (Type # V 11 > cimals. Do not round.) ... Correlation matrix: Variables Paper Glass 10.1768 Paper Glass 0.1768 1SEE MORE QUESTIONSRecommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons IncProbability and Statistics for Engineering and th…StatisticsISBN:9781305251809Author:Jay L. DevorePublisher:Cengage LearningStatistics for The Behavioral Sciences (MindTap C…StatisticsISBN:9781305504912Author:Frederick J Gravetter, Larry B. 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