In this exercise involving paired differences, consider that it is reasonable to assume the populations being compared have approximately the same shape and that the distribution of paired differences is approximately symmetric.Percents of on-time arrivals for flights in 2006 and 2007 were collected for 11 randomly selected airports. Suppose data for these airports follow.AirportPercent On-Time 2006- 2007171.78 68.69268.23 65.88376.98 78.40478.71 75.78578.59 72.45678.67 79.68775.67 77.38875.29 69.98968.39 62.841080.91 77.491176.55 71.42Use ? = 0.05 to test the hypothesis that there is no difference between the median percent of on-time arrivals for the two years.State the null and alternative hypotheses.H0: Median percent on-time in 2006 − Median percent on-time in 2007 ≥ 0Ha: Median percent on-time in 2006 − Median percent on-time in 2007 < 0H0: Median percent on-time in 2006 − Median percent on-time in 2007 ≤ 0Ha: Median percent on-time in 2006 − Median percent on-time in 2007 > 0 H0: Median percent on-time in 2006 − Median percent on-time in 2007 > 0Ha: Median percent on-time in 2006 − Median percent on-time in 2007 = 0H0: Median percent on-time in 2006 − Median percent on-time in 2007 ≠ 0Ha: Median percent on-time in 2006 − Median percent on-time in 2007 = 0H0: Median percent on-time in 2006 − Median percent on-time in 2007 = 0Ha: Median percent on-time in 2006 − Median percent on-time in 2007 ≠ 0Find the value of the test statistic.T + = Find the p-value. (Round your answer to four decimal places.)p-value = What is your conclusion?Do not reject H0. There is sufficient evidence to conclude that there is a significant difference between the median percent of on-time arrivals for the two years.Do not reject H0. There is not sufficient evidence to conclude that there is a significant difference between the median percent of on-time arrivals for the two years. Reject H0. There is sufficient evidence to conclude that there is a significant difference between the median percent of on-time arrivals for the two years.Reject H0. There is not sufficient evidence to conclude that there is a significant difference between the median percent of on-time arrivals for the two years. You may need to use the appropriate appendix table or technology to answer this question.In this exercise involving paired differences, consider that it is reasonable to assume the populations being compared have approximately the same shape and that the distribution of paired differences is approximately symmetric.Percents of on-time arrivals for flights in 2006 and 2007 were collected for 11 randomly selected airports. Suppose data for these airports follow.Percent On-TimeAirport20062007171.7868.6968.2365.88376.9878.40478.7175.78578.5972.45678.6779.68775.6777.3875.2969.9868.3962.841080.9177.491176.5571.42Use a = 0.05 to test the hypothesis that there is no difference between the median percent of on-time arrivals for the two years.State the null and alternative hypotheses.O H,: Median percent on-time in 2006 - Median percent on-time in 2007 20H: Median percent on-time in 2006 - Median percent on-time in 2007 < 0O H: Median percent on-time in 2006 - Median percent on-time in 2007 s0H: Median percent on-time in 2006 - Median percent on-time in 2007 > 0O H: Median percent on-time in 2006 - Median percent on-time in 2007 > 0H: Median percent on-time in 2006 - Median percent on-time in 2007 = 0O H: Median percent on-time in 2006 - Median percent on-time in 2007 = 0H: Median percent on-time in 2006 - Median percent on-time in 2007 = 0O H: Median percent on-time in 2006 - Median percent on-time in 2007 = 0H: Median percent on-time in 2006 - Median percent on-time in 2007 0Find the value of the test statistic.Find the p-value. (Round your answer to four decimal places.)p-value =What is your conclusion?O Do not reject H. There is sufficient evidence to conclude that there is a significant difference betvween the median percent of on-time arrivals for the two years.O Do not reject H. There is not sufficient evidence to conclude that there is a significant difference between the median percent of on-time arrivals for the two years.O Reject H. There is sufficient evidence to conclude that there is a significant difference between the median percent of on-time arrivals for the two years.O Reject H. There is not sufficient evidence to conclude that there is a significant difference between the median percent of on-time arrivals for the two years.

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Description: In this exercise involving paired differences, consider that it is reasonable to assume the populations being compared have approximately the same shape and that the distribution of paired differences is approximately symmetric.Percents of on-time ar

Solution: Null and Alternative Hypotheses: The following null and alternative hypotheses need to be…

Use ? = 0.05 to test the hypothesis that there is no difference between the median percent of on-time arrivals for the two years. State the null and alternative hypotheses. H0: Median percent on-time in 2006 − Median percent on-time in 2007 ≥ 0 Ha: Median percent on-time in 2006 − Median percent on-time in 2007 < 0H0: Median percent on-time in 2006 − Median percent on-time in 2007 ≤ 0 Ha: Median percent on-time in 2006 − Median percent on-time in 2007 > 0 H0: Median percent on-time in 2006 − Median percent on-time in 2007 > 0 Ha: Median percent on-time in 2006 − Median percent on-time in 2007 = 0H0: Median percent on-time in 2006 − Median percent on-time in 2007 ≠ 0 Ha: Median percent on-time in 2006 − Median percent on-time in 2007 = 0H0: Median percent on-time in 2006 − Median percent on-time in 2007 = 0 Ha: Median percent on-time in 2006 − Median percent on-time in 2007 ≠ 0 Find the value of the test statistic. T + = Find the p-value. (Round your answer to four decimal places.) p-value = What is your conclusion? Do not reject H0. There is sufficient evidence to conclude that there is a significant difference between the median percent of on-time arrivals for the two years.Do not reject H0. There is not sufficient evidence to conclude that there is a significant difference between the median percent of on-time arrivals for the two years. Reject H0. There is sufficient evidence to conclude that there is a significant difference between the median percent of on-time arrivals for the two years.Reject H0. There is not sufficient evidence to conclude that there is a significant difference between the median percent of on-time arrivals for the two years.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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In this exercise involving paired differences, consider that it is reasonable to assume the populations being compared have approximately the same shape and that the distribution of paired differences is approximately symmetric.

Percents of on-time arrivals for flights in 2006 and 2007 were collected for 11 randomly selected airports. Suppose data for these airports follow.

Airport	Percent On-Time
	2006-	2007
1	71.78	68.69
2	68.23	65.88
3	76.98	78.40
4	78.71	75.78
5	78.59	72.45
6	78.67	79.68
7	75.67	77.38
8	75.29	69.98
9	68.39	62.84
10	80.91	77.49
11	76.55	71.42

Use ? = 0.05 to test the hypothesis that there is no difference between the median percent of on-time arrivals for the two years.

State the null and alternative hypotheses.

H₀: Median percent on-time in 2006 − Median percent on-time in 2007 ≥ 0
H_a: Median percent on-time in 2006 − Median percent on-time in 2007 < 0H₀: Median percent on-time in 2006 − Median percent on-time in 2007 ≤ 0
H_a: Median percent on-time in 2006 − Median percent on-time in 2007 > 0 H₀: Median percent on-time in 2006 − Median percent on-time in 2007 > 0
H_a: Median percent on-time in 2006 − Median percent on-time in 2007 = 0H₀: Median percent on-time in 2006 − Median percent on-time in 2007 ≠ 0
H_a: Median percent on-time in 2006 − Median percent on-time in 2007 = 0H₀: Median percent on-time in 2006 − Median percent on-time in 2007 = 0
H_a: Median percent on-time in 2006 − Median percent on-time in 2007 ≠ 0

Find the value of the test statistic.

T⁺ =

Find the p-value. (Round your answer to four decimal places.)

p-value =

What is your conclusion?

Do not reject H₀. There is sufficient evidence to conclude that there is a significant difference between the median percent of on-time arrivals for the two years.Do not reject H₀. There is not sufficient evidence to conclude that there is a significant difference between the median percent of on-time arrivals for the two years. Reject H₀. There is sufficient evidence to conclude that there is a significant difference between the median percent of on-time arrivals for the two years.Reject H₀. There is not sufficient evidence to conclude that there is a significant difference between the median percent of on-time arrivals for the two years.

You may need to use the appropriate appendix table or technology to answer this question.
In this exercise involving paired differences, consider that it is reasonable to assume the populations being compared have approximately the same shape and that the distribution of paired differences is approximately symmetric.
Percents of on-time arrivals for flights in 2006 and 2007 were collected for 11 randomly selected airports. Suppose data for these airports follow.
Percent On-Time
Airport
2006
2007
1
71.78
68.69
68.23
65.88
3
76.98
78.40
4
78.71
75.78
5
78.59
72.45
6
78.67
79.68
7
75.67
77.38
75.29
69.98
68.39
62.84
10
80.91
77.49
11
76.55
71.42
Use a = 0.05 to test the hypothesis that there is no difference between the median percent of on-time arrivals for the two years.
State the null and alternative hypotheses.
O H,: Median percent on-time in 2006 - Median percent on-time in 2007 20
H: Median percent on-time in 2006 - Median percent on-time in 2007 < 0
O H: Median percent on-time in 2006 - Median percent on-time in 2007 s0
H: Median percent on-time in 2006 - Median percent on-time in 2007 > 0
O H: Median percent on-time in 2006 - Median percent on-time in 2007 > 0
H: Median percent on-time in 2006 - Median percent on-time in 2007 = 0
O H: Median percent on-time in 2006 - Median percent on-time in 2007 = 0
H: Median percent on-time in 2006 - Median percent on-time in 2007 = 0
O H: Median percent on-time in 2006 - Median percent on-time in 2007 = 0
H: Median percent on-time in 2006 - Median percent on-time in 2007 0
Find the value of the test statistic.
Find the p-value. (Round your answer to four decimal places.)
p-value =
What is your conclusion?
O Do not reject H. There is sufficient evidence to conclude that there is a significant difference betvween the median percent of on-time arrivals for the two years.
O Do not reject H. There is not sufficient evidence to conclude that there is a significant difference between the median percent of on-time arrivals for the two years.
O Reject H. There is sufficient evidence to conclude that there is a significant difference between the median percent of on-time arrivals for the two years.
O Reject H. There is not sufficient evidence to conclude that there is a significant difference between the median percent of on-time arrivals for the two years.

Definition Definition Middle value of a data set. The median divides a data set into two halves, and it also called the 50th percentile. The median is much less affected by outliers and skewed data than the mean. If the number of elements in a dataset is odd, then the middlemost element of the data arranged in ascending or descending order is the median. If the number of elements in the dataset is even, the average of the two central elements of the arranged data is the median of the set. For example, if a dataset has five items—12, 13, 21, 27, 31—the median is the third item in ascending order, or 21. If a dataset has six items—12, 13, 21, 27, 31, 33—the median is the average of the third (21) and fourth (27) items. It is calculated as follows: (21 + 27) / 2 = 24.

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