Upon reaction of 1.27 g of copper sulfate with excess zinc metal, 0.377 g copper metal was obtained as an experimental result according to the equation: CuSO4(aq) + Zn(s) Before the experiment was carried out the following calculation was completed to predict the maximum amount of copper that could be isolated. The answerlwas 0.506 g of Cu. Cu(s) + ZNSO4(aq) mol mol Cu ECu Cuso, 1 mot CuSO, 159.62 g CuS0, mol Cu 63.55 g Cu 1 mot Cu 1 mot CuSO, What is the percent yield?

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Upon reaction of 1.27 g of copper sulfate with
excess zinc metal, 0.377 g copper metal was
obtained as an experimental result according to the
equation:
CUSO4(aq) + Zn(s) Cu(s) + ZNSO4(aq)
Before the experiment was carried out the
following calculation was completed to predict the
maximum amount of copper that could be isolated.
The answerwas 0.506 g of Cu.
E Cuso,
mal
mol Cu
1 mol CuS0,
159.62 g CuS0,
1 mol Cu
63.55 g Cu
1 mot CuSO,
1 mot Cu
What is the percent yield?
report your answer to the tenths place, i.e. one decimal
place.
Transcribed Image Text:Upon reaction of 1.27 g of copper sulfate with excess zinc metal, 0.377 g copper metal was obtained as an experimental result according to the equation: CUSO4(aq) + Zn(s) Cu(s) + ZNSO4(aq) Before the experiment was carried out the following calculation was completed to predict the maximum amount of copper that could be isolated. The answerwas 0.506 g of Cu. E Cuso, mal mol Cu 1 mol CuS0, 159.62 g CuS0, 1 mol Cu 63.55 g Cu 1 mot CuSO, 1 mot Cu What is the percent yield? report your answer to the tenths place, i.e. one decimal place.
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