UPUsSending spaceships to the outer regions of the solar system requires large energies. The slingshot effect is a frequently used method for speedingup spaceships without using much rocket fuel. To use this effect, the spaceship is diverted to pass around one of the inner planets (such as Venus).If the spaceship is sent in the right direction, it will reach to greater speeds after it passes around the planet. You will see the effect at play in thisquestion.A spaceship is sent with an initial velocity of vs = (20 - j+ 30- i) km/s towards a planet. The planet is moving with velocity öpAfter the encounter with the planet, the spaceship emerges to be moving along the +a direction (with a final velocity of the form ig = i). Findthe final speed of the spaceship in units of km/s.= 45i km/s.km/sHint 1: This is an elastic "collision". When you hear the word collision, you usually imagine something that happens quickly: in contrast this collisionhappens over days and perhaps even weeks. But you can use the same equations to treat all.Hint 2: (This is really unnecessary to state, but sometimes I am obliged to state the obvious): Assume that the mass of the planet is much larger thanthe mass of the spaceship.

Initial velocity of the spaceship vs→=20j^+30i^ and initial velocity of the planet vp→=45i^. The…

UP Us Sending spaceships to the outer regions of the solar system requires large energies. The slingshot effect is a frequently used method for speeding up spaceships without using much rocket fuel. To use this effect, the spaceship is diverted to pass around one of the inner planets (such as Venus). If the spaceship is sent in the right direction it will reach to greater speeds after it passes around the planet. You will see the effect at play in this question. A spaceship is sent with an initial velocity of es = (20 -+ 30 - i) km/s towards a planet. The planet is moving with velocity üp = 45i km/s. After the encounter with the planet, the spaceship emerges to be moving along the +z direction (with a final velocity of the form ig = t i) Find %3D the final speed of the spaceship in units of km/s. km/s lirion unuusunlly imagine something that happens quickly: in contrast this collision

UP Us Sending spaceships to the outer regions of the solar system requires large energies. The slingshot effect is a frequently used method for speeding up spaceships without using much rocket fuel. To use this effect, the spaceship is diverted to pass around one of the inner planets (such as Venus). If the spaceship is sent in the right direction it will reach to greater speeds after it passes around the planet. You will see the effect at play in this question. A spaceship is sent with an initial velocity of es = (20 -+ 30 - i) km/s towards a planet. The planet is moving with velocity üp = 45i km/s. After the encounter with the planet, the spaceship emerges to be moving along the +z direction (with a final velocity of the form ig = t i) Find %3D the final speed of the spaceship in units of km/s. km/s lirion unuusunlly imagine something that happens quickly: in contrast this collision

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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An older-model car accelerates from 0 to speed vin 15 s. A newer, more powerful sports car of the same mass accelerates from 0 to 3v in the same time period. Assuming the energy coming from the engine appears only as kinetic energy of the cars, compare the power of the two cars.
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1) A 5-kg particle's momentum is (211, 329) kg*m/s. Calculate its kinetic energy. 2)Calculate the x-component of vSJ. vS = 6 km/s vJ = 9 km/s θ = 23o 3) In Jupiter's frame, the incoming spacecraft is moving rightward and upward, at 45o. The outgoing spacecraft, having already flown by, is going at the same relative speed, but leftward and upward, also at 45o. (See the figures.) You are going to transform back to the sun's frame and calculate the final outgoing speed. You need to follow several steps: Calculate the vector components of the outgoing vSJ. Add Jupiter's vector velocity to get the outgoing vS. Finally calculate the outgoing speed, vS = |vS| in km/s. Enter that as the final answer. use these parameters: vSJ = 4 km/s vJ = 8 km/s
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Consider a binary star system that has bright lines at 656.72 and 656.86 nm,56.46-nm hydrogen line in the rest frame, estimate the speed V of the center of mass of the binary system is 151km/s how do I determine the mass of each star, they orbit in a circular motion.
Suppose that you have found a way to convert the rest energy of any type of matter directly to usable energy with an efficiency of 61.0%. How many liters of water would be sufficient fuel to very slowly push the Moon 1.70 mm away from the Earth? The density of water is ?water=1.00kg/liter, the Earth's mass is ?earth=5.97×1024 kg, the Moon's mass is ?moon=7.36×1022 kg, and the separation of the Earth and Moon is ?E,M=3.84×108 m.
Question 14 Particle A has 16 times the mass of particle B, but they both have the same value for the kinetic energy. What is the ratio of their speeds V,/V,? (PAMP1435F20) a) 04 b) O1 c) O32 d) O 64 e) O 16
The escape velocity from a massive object is the speed needed to reach an infinite distance from it and have just slowed to a stop, that is, to have just enough kinetic energy to climb out of the gravitational potential well and have none left. You can find the escape velocity by equating the total kinetic and gravitational potential energy to zero E=12mv2esc−GmM/r=0E=12mvesc2−GmM/r=0 vesc=2GM/r−−−−−−√vesc=2GM/r where GG is Newton's constant of gravitation, MM is the mass of the object from which the escape is happening, and rr is its radius. This is physics you have seen in the first part of the course, and you should be able to use it to find an escape velocity from any planet or satellite. For the Earth, for example the escape velocity is about 11.2 km/s, and for the Moon it is 2.38 km/s. A very important point about escape velocity: it does not depend on what is escaping. A spaceship or a molecule must have this velocity or more away from the center of the planet to be free…