uniform ball with mass m and diameter d is supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the tension in the wire. L on first derive the expression for the tension. wton's First Law EF = mponents of force that makes this so is ΣFΤ = fying this results to T= (4) zing the figure above, we arrive at (4) = sqrt( 2+ ostitution, we arrive at the following: T= + 2 sqt ( pall has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal to T= 0.370 N

College Physics
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Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Problem
A solid uniform ball with massm and diameter dis supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the tension in the wire.
L
d
Solution
a)
Let us first derive the expression for the tension.
By Newton's First Law
ΣF
the components of force that makes this so is
EF = T
= 0
Simplifying this results to
T=
(4)
Analyzing the figure above, we arrive at
(4) = sqt
2+
By substitution, we arrive at the following:
T=
+2
sqrt (
))
If the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal to
T =
0.370 N
Transcribed Image Text:Problem A solid uniform ball with massm and diameter dis supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the tension in the wire. L d Solution a) Let us first derive the expression for the tension. By Newton's First Law ΣF the components of force that makes this so is EF = T = 0 Simplifying this results to T= (4) Analyzing the figure above, we arrive at (4) = sqt 2+ By substitution, we arrive at the following: T= +2 sqrt ( )) If the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal to T = 0.370 N
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