I need help with all the parts. **Problem Description:**A 25-kg uniform beam with a length of 12 m is connected to a wall through a hinged connection and a cable. The beam supports a load of 75 kg. Draw a free-body diagram for the beam and determine:a. The torque produced by the load with respect to point C in Newton-meters.b. The tension in the cable in Newtons.c. The x component of the reaction force (Rx) at point C in Newtons.d. The y component of the reaction force (Ry) at point C in Newtons.e. The direction of Ry.**Diagram Explanation:**The diagram illustrates a beam connected horizontally to a wall at point C. A cable forms a 30-degree angle with the beam, supporting it by being attached at the beam's free end. A downward load of 75 kg is applied at the beam's free end.- The beam's total length is 12 m, and it supports the 75 kg weight at 9 m from the wall (point C).- The cable is shown making a 30-degree angle with the beam. - The beam's weight (Wb) is assumed to act at its midpoint, i.e., 6 m from the wall.**Answer Options:**1. 12,8782. 138.63. 10,9324. 19815. 93266. Upward7. Downward8. 287.49. 223.710. 735011. 384212. 882013. 228714. 163.515. 1563

Given: Mass of load, m=75 kg Mass of rod, 25 kg Distance of load from point c=12 m Distance of COM of rod from point c=6 m Distance from the point at which rope is attached to the rod to the point c=9 m. The free body diagram is drawn below.The formula to determine the torque is τ=F×rτ=Fr sinθ where F is the applied force which is equal to mg here and r is the perpendicular distance between the point of application of force and axis of rotation. Here the F and r are perpendicular to each other therefore θ=90°. Substituting the given values gives τ=mg×r sin90°τ=75 kg×9.8 m/s2×12 mτ=8820 N.mThe free body diagram is drawn below. From the diagram it can be seen that mg×12m+Mg×6m=τsin 30°×9 m75 kg×9.8 m/s2×12 m+25 kg×9.8 m/s2×6 m=τ×0.5×9 m τ=102904.5 τ=2286.66 N The x component of reaction force will be τ cos 30°. Substitute the respective values and calculate the x-component. Rx=τ cos 30°Rx=2286.66×32Rx=1980.30 NThe y component of reaction force will be τ sin 30°. Substitute the respective values and calculate the x-component. Ry=τ sin 30°Ry=2286.66×12Ry=1143.33 NThe direction of Ry will be upward that is positive y-axis.