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13. Calculate the magnitude of the acceleration of the asteroid, relative to the spaceship. (a) 0.2083 m/s² (b) 0.4163 m/s² (c) 0.1387 m/s² (d) 0.4855 m/s²

13. Calculate the magnitude of the acceleration of the asteroid, relative to the spaceship. (a) 0.2083 m/s² (b) 0.4163 m/s² (c) 0.1387 m/s² (d) 0.4855 m/s²

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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### Asteroid and Spaceship Physics Problem Set In the depths of space, asteroid miners attach a cable between their 3,694-kg spaceship and a relatively small 1476-kg asteroid. The ship and asteroid are initially at rest 751 m apart. They begin to “reel in” the asteroid under a constant tension force of 512.0 N. We are going to calculate how long it takes for them to meet. This is a somewhat complicated question involving several different concepts, so let’s take it step by step. #### Task 1: Free-Body Diagrams 11. **Draw free-body diagrams for the asteroid, and for the spaceship.** *Note: In this step, you would need to draw the diagrams showing all the forces acting on both the asteroid and the spaceship. Typically, these diagrams would include gravitational forces and tension forces.* #### Task 2: Calculating Accelerations 12. **Calculate the magnitudes of the accelerations of the asteroid, and of the spaceship, respectively.** a) \( a_a = 0.3469 \, \text{m/s}^2; \quad a_s = 0.1386 \, \text{m/s}^2 \) b) \( a_a = 0.1386 \, \text{m/s}^2; \quad a_s = 0.3469 \, \text{m/s}^2 \) c) \( a_a = 0.1388 \, \text{m/s}^2; \quad a_s = 0.2775 \, \text{m/s}^2 \) d) \( a_a = 0.2775 \, \text{m/s}^2; \quad a_s = 0.1388 \, \text{m/s}^2 \) #### Task 3: Acceleration of Asteroid Relative to Spaceship 13. **Calculate the magnitude of the acceleration of the asteroid, relative to the spaceship.** a) \( 0.2083 \, \text{m/s}^2 \) b) \( 0.4163 \, \text{m/s}^2 \) c) \( 0.1387 \, \text{m/s}^2 \) d) \(
Transcribed Image Text:### Asteroid and Spaceship Physics Problem Set In the depths of space, asteroid miners attach a cable between their 3,694-kg spaceship and a relatively small 1476-kg asteroid. The ship and asteroid are initially at rest 751 m apart. They begin to “reel in” the asteroid under a constant tension force of 512.0 N. We are going to calculate how long it takes for them to meet. This is a somewhat complicated question involving several different concepts, so let’s take it step by step. #### Task 1: Free-Body Diagrams 11. **Draw free-body diagrams for the asteroid, and for the spaceship.** *Note: In this step, you would need to draw the diagrams showing all the forces acting on both the asteroid and the spaceship. Typically, these diagrams would include gravitational forces and tension forces.* #### Task 2: Calculating Accelerations 12. **Calculate the magnitudes of the accelerations of the asteroid, and of the spaceship, respectively.** a) \( a_a = 0.3469 \, \text{m/s}^2; \quad a_s = 0.1386 \, \text{m/s}^2 \) b) \( a_a = 0.1386 \, \text{m/s}^2; \quad a_s = 0.3469 \, \text{m/s}^2 \) c) \( a_a = 0.1388 \, \text{m/s}^2; \quad a_s = 0.2775 \, \text{m/s}^2 \) d) \( a_a = 0.2775 \, \text{m/s}^2; \quad a_s = 0.1388 \, \text{m/s}^2 \) #### Task 3: Acceleration of Asteroid Relative to Spaceship 13. **Calculate the magnitude of the acceleration of the asteroid, relative to the spaceship.** a) \( 0.2083 \, \text{m/s}^2 \) b) \( 0.4163 \, \text{m/s}^2 \) c) \( 0.1387 \, \text{m/s}^2 \) d) \(
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