### Equivalent Resultant Force Calculation#### Given Information:- **Assume:** \( F_1 = 250 \, \text{lb} \), \( F_2 = 80 \, \text{lb} \), and \( F_3 = 120 \, \text{lb} \)- **Refer to Figure 1:** Replace the loading by an equivalent resultant force.#### Figure Description:The figure displays a horizontal beam with three forces acting on it at various points:- \( F_1 \) (250 lb), an upward force applied 3 feet from point \( A \).- \( F_2 \) (80 lb), another upward force applied 3 feet to the right of the position of \( F_1 \).- \( F_3 \) (120 lb), a downward force applied 5 feet to the right of the position of \( F_2 \).### Part A: Magnitude of the Equivalent Resultant ForceYou need to determine the magnitude of the equivalent resultant force (\( F_R \)).**Express your answer in pounds to three significant figures:**\[ F_R = \boxed{\phantom{answer}} \, \text{lb} \]### Part B: Angle of the Equivalent Resultant ForceDetermine the angle between the equivalent resultant force and the positive \( x \)-axis.**Express your answer in degrees to three significant figures:**\[ \theta = \boxed{\phantom{answer}} \, ° \]*Note: The angle \( \theta \) is measured counterclockwise from the positive \( x \)-axis.* ### Problem StatementAssume \( F_1 = 250 \, \text{lb} \), \( F_2 = 80 \, \text{lb} \), and \( F_3 = 120 \, \text{lb} \). Replace the loading by an equivalent resultant force.### FigureThe figure illustrates a beam with three forces acting on it. The forces are denoted as \( F_1 \), \( F_2 \), and \( F_3 \). #### Description of the Diagram- The beam is horizontally aligned and anchored at point \( A \).- \( F_1 \) is downward acting 3 feet away from point \( A \).- \( F_2 \) is at an angle of 30° from the horizontal, acting 5 feet away from point \( A \) to the right.- \( F_3 \) is directed downwards and to the left, forming an angle from the vertical depicted in the diagram, acting 4 feet away from point \( A \) horizontally and 3 feet vertically.#### Axes: The diagram references an \( x \)-\( y \) coordinate system where:- The x-axis is horizontal.- The y-axis is vertical.### Part CSpecify where the resultant's line of action intersects the member measured from \( A \).**Express your answer in feet to three significant figures.**```d = [input box] ft```**Submit Button with Request Answer Link**Use this information to solve for the resultant force and its location of intersection relative to point \( A \).

F1=250lbF2=80lbF3=120lbTo find resultant, it's direction and distance from point A

ume F₁ = 250 lb, F₂2 = 80 lb, and F3 = 120 lb in ure 1). Replace the loading by an equivalent resultant e. re 3 ft L. 3 ft -3 ft 30° 1 of 1 Express your answer in pounds to three significant figures. FR = Submit Part B 15. ΑΣΦ | 11 | vec 1 → 0 = Request Answer Determine the angle between the equivalent resultant force and the x axis. Express your answer in degrees to three significant figures. AEO 1 vec 1 SMED ? A ? lb °, measured counterclockwise from the positive z axis

ume F₁ = 250 lb, F₂2 = 80 lb, and F3 = 120 lb in ure 1). Replace the loading by an equivalent resultant e. re 3 ft L. 3 ft -3 ft 30° 1 of 1 Express your answer in pounds to three significant figures. FR = Submit Part B 15. ΑΣΦ | 11 | vec 1 → 0 = Request Answer Determine the angle between the equivalent resultant force and the x axis. Express your answer in degrees to three significant figures. AEO 1 vec 1 SMED ? A ? lb °, measured counterclockwise from the positive z axis

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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