ult 3H
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Question
Instructions: In Order to answer the given the first picture is the guide to answer the given please provide detailed step by step solution.
Note: Elimination & Substitution are required
![ulth
3H
3F](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F650ac3a2-5207-4c09-9253-789fa603c52d%2Fd2ff5f07-44cc-430b-b161-1715716056f9%2Fmxxotoi_processed.jpeg&w=3840&q=75)
Transcribed Image Text:ulth
3H
3F
![The impedances are now:
V(s)
Z(s) =
I(s)
Laplace Transtorm
Resistor: Z(s) =R
Inductor: Z(s) = sL
Capacitor: Z(s)
Step 1
Convert to imped ance.
step a
Mosh Anolysis
ΙΩ
5Ω
ww
u(1)
1H (1)
3.
%3D
Ia
©57,+sI, +-T,)=0
+3
(s+S+흥) Lu-흥 20
3
Elimination
Step 3
Step
-3 [(st377,-37,=1]
(s+3 )I, - 37,= /
912=-3
9I, = 0
(55+s*+3JI3 - 31, = 0
- 3I, + (s²4 55+3)I, =
Jutition
IIa =-3
(53+8524/85+9II1=0
(-s³-85*-185)Fa = -3
(S+ 3)I, - 3(-
- 3
Ia ==53-85^_11s
- 3
(S+3)I, = 1+
3.
53+852+185
StS
S+3
ell](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F650ac3a2-5207-4c09-9253-789fa603c52d%2Fd2ff5f07-44cc-430b-b161-1715716056f9%2Figjt0ng_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The impedances are now:
V(s)
Z(s) =
I(s)
Laplace Transtorm
Resistor: Z(s) =R
Inductor: Z(s) = sL
Capacitor: Z(s)
Step 1
Convert to imped ance.
step a
Mosh Anolysis
ΙΩ
5Ω
ww
u(1)
1H (1)
3.
%3D
Ia
©57,+sI, +-T,)=0
+3
(s+S+흥) Lu-흥 20
3
Elimination
Step 3
Step
-3 [(st377,-37,=1]
(s+3 )I, - 37,= /
912=-3
9I, = 0
(55+s*+3JI3 - 31, = 0
- 3I, + (s²4 55+3)I, =
Jutition
IIa =-3
(53+8524/85+9II1=0
(-s³-85*-185)Fa = -3
(S+ 3)I, - 3(-
- 3
Ia ==53-85^_11s
- 3
(S+3)I, = 1+
3.
53+852+185
StS
S+3
ell
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