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uestion 28 The half-reaction occurring at the anode in the balanced reaction shown below is 3MNO 4 (aq) + 24H (aq) + 5Fe (5) → 3Mn 2+ (aq) + 5Fe 3+ (aq) + 12H 20 () O Fe (5) → Fe2+ (aq) + 2e O 2MN04 (aq) + 12H (aq) + 6e 2MN2+ (aq) + 3H20 (I) Fe2+ (aq) Fe3+ (aq) + e Fe (s) Fe3+ (aq) + 3e" O Mn04 (aq) + 8H* (aq) + 5e Mn* (aq) + 4H2O (I)

uestion 28 The half-reaction occurring at the anode in the balanced reaction shown below is 3MNO 4 (aq) + 24H (aq) + 5Fe (5) → 3Mn 2+ (aq) + 5Fe 3+ (aq) + 12H 20 () O Fe (5) → Fe2+ (aq) + 2e O 2MN04 (aq) + 12H (aq) + 6e 2MN2+ (aq) + 3H20 (I) Fe2+ (aq) Fe3+ (aq) + e Fe (s) Fe3+ (aq) + 3e" O Mn04 (aq) + 8H* (aq) + 5e Mn* (aq) + 4H2O (I)

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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> A Moving to the next question prevents changes to this answer. uestion 28 The half-reaction occurring at the anode in the balanced reaction shown below is 3MNO 4 (aq) + 24H * (aq) + 5Fe (s) → 3Mn 2+ 3+ (aq) + 5Fe (aq) + 12H 20 (O O Fe (s) → Fe2+ (aq) + 2e O 2MN04 (aq) + 12H (aq) + 6e 2MN2+ (aq) + 3H20 (1) Fe2+ (aq) – Fe3+ (aq) + e Fe (5) → Fe3+ (aq) + 3e" O Mn04 (aq) + 8H* (aq) + 5e → Mn2+ (aq) + 4H20 (1) A Moving to the next question prevents changes to this answer. 93 OType here to search
Transcribed Image Text:> A Moving to the next question prevents changes to this answer. uestion 28 The half-reaction occurring at the anode in the balanced reaction shown below is 3MNO 4 (aq) + 24H * (aq) + 5Fe (s) → 3Mn 2+ 3+ (aq) + 5Fe (aq) + 12H 20 (O O Fe (s) → Fe2+ (aq) + 2e O 2MN04 (aq) + 12H (aq) + 6e 2MN2+ (aq) + 3H20 (1) Fe2+ (aq) – Fe3+ (aq) + e Fe (5) → Fe3+ (aq) + 3e" O Mn04 (aq) + 8H* (aq) + 5e → Mn2+ (aq) + 4H20 (1) A Moving to the next question prevents changes to this answer. 93 OType here to search
Expert Solution
Step 1

We know that in the half cell reaction 

The reduction occurs at cathode and oxidation occurs at anode. 

Based on this we can say that which is going to oxides in the half cell reaction in the above chemical equation.we can see that iron is oxidizing to Iron(III) 

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