The relevant half-reaction equations are given below. Half-Reaction Equations CH₂COOH(aq) + 4 H(aq) + E= 14 e-→ C₂H5OH(aq) + H₂O(1) +0.58 V Eº +1.23 V O₂(g) + 4 H'(aq) + 4 e-→ 2 11 H₂O(1) = If the reference half-cell were changed from the standard hydrogen half- cell to the standard cadmium half-cell, then the reduction potential for Equation I would become

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Chapter1: Chemical Foundations
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The amount of ethanol, C₂H5OH(aq). in a person's breath can be
measured in an electrochemical cell.
The relevant half-reaction equations are given below.
Half-Reaction Equations
CH3COOH(aq) + 4 H*(aq) + E =
+0.58
14 e-→ C₂H5OH(aq) +
H₂O(l)
O2(g) + 4 H*(aq) + 4 e- →2
11
H₂O(l)
O-0,98 V
O +0.98 V
If the reference half-cell were changed from the standard hydrogen half-
cell to the standard cadmium half-cell, then the reduction potential for
Equation I would become
O +0.18 V
>&
O-0.18 V
V
E =
+1.23
V
Transcribed Image Text:The amount of ethanol, C₂H5OH(aq). in a person's breath can be measured in an electrochemical cell. The relevant half-reaction equations are given below. Half-Reaction Equations CH3COOH(aq) + 4 H*(aq) + E = +0.58 14 e-→ C₂H5OH(aq) + H₂O(l) O2(g) + 4 H*(aq) + 4 e- →2 11 H₂O(l) O-0,98 V O +0.98 V If the reference half-cell were changed from the standard hydrogen half- cell to the standard cadmium half-cell, then the reduction potential for Equation I would become O +0.18 V >& O-0.18 V V E = +1.23 V
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