U. U. Width b into paper

Q: Problem 2. Using the provided FBD below, solve for the magnitudes of TA, IB, and Tc required for…

A:

Q: The cross section is elliptical as shown in the figure and the uniform thickness t=5mm The…

A: Given, Internal Pressure, P = 1.4 MPaThickness, t = 5 mmRadius, r = 0.15 m = 150 mm Circumferential…

Q: For the beam and loading shown below, determine the beam deflection at point H. Assume that EI = 6.4…

A: Given:- EI=6.4×104 KN.m2w=3.6 KN/mLAB=3.7 mLBC=7.4 mLCH=3.7 m To find:- Deflection at point H

Q: Problem 6 (25 minutes) The following rigid beam is supported by a pin and two steel rods (E=29,000…

A: Displacement at D = 0.031 in.Explanation:

Q: Determine the shear flow that acts in the shape at points A-D.

A:

Q: 30 kN 30 kN 30 kN D 20 kN C. E 4 m B -2 m--2 m- m-2 m- EA = constant E = 200 GPa A = 5000 mm?

A:

Q: 8.36 Consider fully developed laminar flow in the annulus between two concentric pipes. The outer…

A: Given: There is fully developed laminar flow in the annulus between concentric pipes in which outer…

Q: The 36-kg homogeneous smooth sphere rests on the 22° incline A and bears against the smooth vertical…

A:

Q: Consider a square bar 30 mm on side and 2.5 m long, having a material yield point 254 (in MPa). An…

A:

Q: A rectangular gate AB in Figure 1 is 1.2 m long and 0.8 m into the paper. Neglecting atmospheric…

A: To find hydrostatic force

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A: Laminar flow between parallel plates- Velocity profile u=v(y/h) Gap height h=5 mm=0.005 m, Specific…

Q: Q.4 A non-Newtonian fluid is flowing in a floor having height 5mm and with a free stream velocity of…

A: Given data- Non-Newtonian fluid- height h=5 mm, Free stream velocity=0.5 m/s, Yield stress=38 MPa,…

Q: The 75-lb force P is applied to the 160-lb crate, which is stationary before the force is applied.…

A:

Q: The 350-N lamp is supported by three steel rods connected by a ring at A. The average normal stress…

A: Appreciate if there is detailed work with explanation and finds you helpful for ease of…

Q: 2. The block of weight W2 is being held in its position by two cylindrical rollers resting on…

A: For maximum value of W2 block should be in equilibrium.

Q: 2. Axilly loaded bar, fixed-fixed on both ends An axial load P=200x10³ N is applied on a bar as…

A:

Q: state true/false. and if false justify For horizontal flow of a liquid in a rectangular duct between…

A: The statement given here is Shear stress varies from Zero at the plates to Maximum at centreline,…

Q: ly ôf 3.5 m/s through a circular pipe, knowing that the flow is laminar with a friction factor…

A:

Q: PROBLEM 7 The velocity distribution in a pipe of radius ro is given by: - Annular Ring when m <1…

A: Since you have asked multiple question, we will solve the first question for you. If youwant any…

Q: PROBLEMI Psd the equation of motion of the uniform rigid bar OA of length I and mass m shown in…

A:

Q: Problem 4 An open-topped tank with square bottom, 0.9 m on a side is 0.60 m high. It floats in…

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Q: An aircraft hanger has a semi-circular cross section of diameter 50m and its longitudinal axis is…

A: Hangars for airplanes are usually referred to as "glorified garages." They can range from basic…

Q: A flow of a viscous fluid with μ = 1.0 u a velocity distribution given by u = The shear stress at y…

A: velocity distribution = 0.9y - y2To Find :The Shear stress at y = 0.45 m

Q: Which one is correct? A. Increasing additional load means increasing exposed depth in a fluid. B.…

A:

Q: The 58-kg crate is stationary when the force P is applied. Determine the resulting acceleration of…

A: M=58kg

Q: Body A has a mass of 25 kg and body B has a mass of 50 kg. The coefficient of friction for all…

A:

Q: A flat plate of 1.5 m² is being pulled over a fixed flat surface at a constant velocity of 10.5 m/s.…

A: Given data in question  Area 1.5 m2 Velocity 10.5 m/s Distance 0.0025 m Force 4.1 N To find out…

Q: 1. A barrel in the form of a frustum of a cone with a radius of 3m at the bottom and 6m at the top.…

A: Density of oil = 0.85*1000 = 850kg/m3

Q: ing girder level P(t) = 890 sin 5.3t (N). Assuming 5% of critical damping. Determine: (a) the steady…

A: the problem has been solved by basic of dynamics. to solve first we have to change units into mks…

Q: Find the height H in terms of R shown in the figure, for which the hydrostatic force on the…

A: The hydrostatic force on the rectangular panel is equal to the hydrostatic force on the semicircle…

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A: When central middle plate will move then both upper and lower plates will resist it's motion and…

Q: concentrated load that this beam can carry besides its own weight. Use fc = 7MPA, fs = 124 MPa, n =…

A:

Q: Tm- L+A Q1 A direct extrusion operation produces the cross section shown in Figure Q1 from a brass…

A:

Q: A steady flow between two parallel plates is fully developed and laminar. The distance between the…

A: Two parallel plates are given placed a distance h apart. Flow is steady, laminar, and fully…

Q: The homogeneous cylinder of weight Wrests in a frictionless right-angled corner. Determine the…

A:

Q: Derive the expression

A: Expression for change in length of the block

Q: り 45ON 120 N 12 20ON J30 360 N a. Determine the x-component of the resultant. b. Determine the…

A: Given data in question  Forces  Angles To find out  X component  Resultant magnitude  Equilibrant…

Q: A third spring of constant k3and a weight W3are added to the system of Example 5.3. Determine the…

A:

Q: 4.In turbulent flow the particals moves in all directions and randomly mixes with each other. O true…

A: Turbulent flow is a type of fluid (gas or liquid) flow in which the fluid undergoes irregular…

Q: 1. The Dam ABC has a width of 30 m into the paper and the dam bottom length is 60m. The dam material…

A: We will calculate each moment and find FOS.

Q: My w1 = 400 KN W, W, W2 What maximum value of W2 it can be before slipping of the block happens?…

A: To determine: maximum value of W2 before slipping of the block occurs normal reaction force against…

Q: Q.43 Consider a steel (E = 200 GPa) column hinged on one side and fixed on the other side. Its…

A: Given data, E=200 GPa, Height (h) =1.5 m Cross-section = 20 mm×25 mm

Braced cuts

The braced cut is a method of providing lateral support to the soil in foundation trenches, to prevent the trenches from deformation by the caving in of soil and resisting it from moving laterally. During shallow excavation in firm soil, generally, slopes are provided to resist the caving in of soil. During shallow excavation in soft soil and deep excavation, the chances of caving in of soil increase. Hence, it becomes necessary to make a provision to resist the deformation of trenches due to caving in of soil. The braced cut is the method used for such conditions. The excavation using braced cuts is a bit uneconomical as compared to the traditional open-cut excavation method but provides better safety than the cut excavation method.