Tyre Spoke Hub Rim Spoke Nipple Let us consider a bicycle wheel spinning at a rate of 50 revolutions per minute (rpm)--or 100 s-1.-about its center. A good approximation for the wheel is that all its mass is at the edge, thus we can say that the moment of inertia is given by I = MR. Ignoring the mass of the spokes, the rim has a mass of 2 kg and a radius of 75 cm. The angular momentum L is O 6.9 kg - m² /s O 5.9 kg - m² /s O 7.8 kg - m2 /s O 8.5 kg · m² /s

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Suppose all the mass of the wheel was in the spokes
instead of the rim. If the wheel had the same mass
and angular velocity, would it have a smaller or
greater angular momentum than from before?
O The angular momentum would be smaller than before
O The angular momentum would be greater than before
O The angular momentum would be the same
Transcribed Image Text:Suppose all the mass of the wheel was in the spokes instead of the rim. If the wheel had the same mass and angular velocity, would it have a smaller or greater angular momentum than from before? O The angular momentum would be smaller than before O The angular momentum would be greater than before O The angular momentum would be the same
Tyre
Spoke
Hub
Rim
Spoke
Nipple
Let us consider a bicycle wheel spinning at a rate of
50 revolutions per minute (rpm)--or 100 s-1.-about
its center. A good approximation for the wheel is that
all its mass is at the edge, thus we can say that the
moment of inertia is given by I = MR. Ignoring the
mass of the spokes, the rim has a mass of 2 kg and a
radius of 75 cm. The angular momentum L is
O 6.9 kg - m² /s
O 5.9 kg - m² /s
O 7.8 kg - m2 /s
O 8.5 kg - m2 /s
Transcribed Image Text:Tyre Spoke Hub Rim Spoke Nipple Let us consider a bicycle wheel spinning at a rate of 50 revolutions per minute (rpm)--or 100 s-1.-about its center. A good approximation for the wheel is that all its mass is at the edge, thus we can say that the moment of inertia is given by I = MR. Ignoring the mass of the spokes, the rim has a mass of 2 kg and a radius of 75 cm. The angular momentum L is O 6.9 kg - m² /s O 5.9 kg - m² /s O 7.8 kg - m2 /s O 8.5 kg - m2 /s
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