A wagon wheel heading down south from the land of the pines consists of a thin ring having a mass of me and six spokes made from slender rods with each having a mass of m... Tw Variable Value mc 7 kg mr 1.3 kg Tw 0.85 m a.) What is the moment of inertia through the center of the wheel in kg - m²? b.) What is the moment of inertia about point A in kg - m²?? A

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### Educational Resource: Moment of Inertia of a Wagon Wheel

**Introduction:**
A wagon wheel heading down south from the land of the pines consists of a thin ring having a mass of \( m_c \) and six spokes made from slender rods with each having a mass of \( m_r \).

**Diagram Explanation:**
In the diagram, a wagon wheel is depicted, showing a thin circular ring with six internal spokes. The wheel's parts and key points are labeled:
- **C** at the center of the wheel.
- **A** at the point where the wheel touches the ground.
- The variables shown in the diagram include:
  - \( r_w \): the radius of the wheel.
  - \( m_c \): the mass of the circular ring.
  - \( m_r \): the mass of each spoke.

**Table of Variables and Their Values:**

\[
\begin{array}{|c|c|}
\hline
\text{Variable} & \text{Value} \\
\hline
m_c & 7 \, \text{kg} \\
\hline
m_r & 1.3 \, \text{kg} \\
\hline
r_w & 0.85 \, \text{m} \\
\hline
\end{array}
\]

**Questions:**
a.) What is the moment of inertia through the center of the wheel in \( \text{kg} \cdot \text{m}^2 \)?

b.) What is the moment of inertia about point \( A \) in \( \text{kg} \cdot \text{m}^2 \)?

**Detailed Information:**
1. **Moment of Inertia through the Center (C):**
   For calculating the moment of inertia of the wheel through its center \( C \), consider the contributions from both the thin ring and the spokes:
   - The moment of inertia of the ring ( \( I_{\text{ring}} \) ):
     \[
     I_{\text{ring}} = m_c \cdot r_w^2
     \]
   - The moment of inertia of each spoke (assumed as a slender rod rotating about one end):
     \[
     I_{\text{spoke}} = \frac{1}{3} m_r \cdot r_w^2
     \]
     Since there are six spokes,
Transcribed Image Text:### Educational Resource: Moment of Inertia of a Wagon Wheel **Introduction:** A wagon wheel heading down south from the land of the pines consists of a thin ring having a mass of \( m_c \) and six spokes made from slender rods with each having a mass of \( m_r \). **Diagram Explanation:** In the diagram, a wagon wheel is depicted, showing a thin circular ring with six internal spokes. The wheel's parts and key points are labeled: - **C** at the center of the wheel. - **A** at the point where the wheel touches the ground. - The variables shown in the diagram include: - \( r_w \): the radius of the wheel. - \( m_c \): the mass of the circular ring. - \( m_r \): the mass of each spoke. **Table of Variables and Their Values:** \[ \begin{array}{|c|c|} \hline \text{Variable} & \text{Value} \\ \hline m_c & 7 \, \text{kg} \\ \hline m_r & 1.3 \, \text{kg} \\ \hline r_w & 0.85 \, \text{m} \\ \hline \end{array} \] **Questions:** a.) What is the moment of inertia through the center of the wheel in \( \text{kg} \cdot \text{m}^2 \)? b.) What is the moment of inertia about point \( A \) in \( \text{kg} \cdot \text{m}^2 \)? **Detailed Information:** 1. **Moment of Inertia through the Center (C):** For calculating the moment of inertia of the wheel through its center \( C \), consider the contributions from both the thin ring and the spokes: - The moment of inertia of the ring ( \( I_{\text{ring}} \) ): \[ I_{\text{ring}} = m_c \cdot r_w^2 \] - The moment of inertia of each spoke (assumed as a slender rod rotating about one end): \[ I_{\text{spoke}} = \frac{1}{3} m_r \cdot r_w^2 \] Since there are six spokes,
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