A uniform thin rod of mass M = 3.37 kg pivots about an axis through its center and perpendicular to its length. Two small bodies, each of mass m = 0.219 kg, are attached to the ends of the rod. What must the length L of the rod be so that the moment of inertia of the three-body system with respect to the described axis is I = 0.975 kg-m² ? L = m m m L
A uniform thin rod of mass M = 3.37 kg pivots about an axis through its center and perpendicular to its length. Two small bodies, each of mass m = 0.219 kg, are attached to the ends of the rod. What must the length L of the rod be so that the moment of inertia of the three-body system with respect to the described axis is I = 0.975 kg-m² ? L = m m m L
University Physics Volume 1
18th Edition
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter11: Angular Momentum
Section: Chapter Questions
Problem 60P: A uniform rod of mass 200 g and length 100 cm is free to rotate in a horizontal plane around a fixed...
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![A uniform thin rod of mass M
= 3.37 kg pivots about an axis through its center and perpendicular to its length. Two small
bodies, each of mass m =
0.219 kg, are attached to the ends of the rod. What must the length L of the rod be so that the moment
of inertia of the three-body system with respect to the described axis is I = 0.975 kg-m? ?
L =
m
M.
m
m
L](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1dd80890-34f3-42a2-96e7-3fec6dc24d2c%2Fb1c3091c-bfb9-4c19-8886-cf7a2b8f3509%2F9ki2q3hm_processed.png&w=3840&q=75)
Transcribed Image Text:A uniform thin rod of mass M
= 3.37 kg pivots about an axis through its center and perpendicular to its length. Two small
bodies, each of mass m =
0.219 kg, are attached to the ends of the rod. What must the length L of the rod be so that the moment
of inertia of the three-body system with respect to the described axis is I = 0.975 kg-m? ?
L =
m
M.
m
m
L
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