Type the following answers using the formats given. Use only the format '1+' or '1-' for the charge on an ion. If only one electron is present in the half-cell reaction, type the answer as e- instead of 1e-. Half-cell Equation Au3+(ag) + 3 e - Au(s) Typed Answer Au3+(aq) + 3e- > Au(s) Balanced Equation 2 Au3+(aq) + 3 Zn(s) - 2 Au(s) + 3 Zn2+(aq) Typed Answer 2AU3+(aq) + 3Zn(s) > 2Au(s) + 3Zn2+(aq) (b) Write the half-cell reaction for the oxidation. (c) Write the half-cell reaction for the reduction. (d) Write the balanced equation for the cell reaction. Keep substances in the order given in the original equation.
Type the following answers using the formats given. Use only the format '1+' or '1-' for the charge on an ion. If only one electron is present in the half-cell reaction, type the answer as e- instead of 1e-. Half-cell Equation Au3+(ag) + 3 e - Au(s) Typed Answer Au3+(aq) + 3e- > Au(s) Balanced Equation 2 Au3+(aq) + 3 Zn(s) - 2 Au(s) + 3 Zn2+(aq) Typed Answer 2AU3+(aq) + 3Zn(s) > 2Au(s) + 3Zn2+(aq) (b) Write the half-cell reaction for the oxidation. (c) Write the half-cell reaction for the reduction. (d) Write the balanced equation for the cell reaction. Keep substances in the order given in the original equation.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![Consider the following reaction.
Fe3+(aq) + Sn2+(aq)
→ Fe2+(aq) + Sn4+(aq)
(a) Select all that apply.
Sn2+ is the reducing agent.
Fe3+ is the substance being reduced.
Fe3+ is the substance being oxidized.
Fe3+
is the reducing agent.
Sn2+ is the substance being reduced.
Fe3+ is the oxidzing agent.
Sn2+ is the oxidzing agent.
Sn2+ is the substance being oxidized.
Type the following answers using the formats given. Use only the format '1+' or '1-' for the charge on an ion. If only one electron is present in the half-cell reaction, type the answer as e- instead of 1e-.
Half-cell Equation
Au3+(aq) + 3 e¯ →
Au(s)
Typed Answer
Au3+(aq) + 3e- > Au(s)
Balanced Equation 2 Au3+(aq) + 3 Zn(s)
2 Au(s) + 3 Zn²+(aq)
Typed Answer
2AU3+(aq) + 3Zn(s) > 2Au(s) + 3Zn2+(aq)
(b) Write the half-cell reaction for the oxidation.
(c) Write the half-cell reaction for the reduction.
(d) Write the balanced equation for the cell reaction. Keep substances in the order given in the original equation.
O O O](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9e4d942c-31fd-424b-b59a-899d7214a995%2Fb616aa28-72c8-4689-8c4d-beba4bb7d527%2Fvjiqq5j_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Consider the following reaction.
Fe3+(aq) + Sn2+(aq)
→ Fe2+(aq) + Sn4+(aq)
(a) Select all that apply.
Sn2+ is the reducing agent.
Fe3+ is the substance being reduced.
Fe3+ is the substance being oxidized.
Fe3+
is the reducing agent.
Sn2+ is the substance being reduced.
Fe3+ is the oxidzing agent.
Sn2+ is the oxidzing agent.
Sn2+ is the substance being oxidized.
Type the following answers using the formats given. Use only the format '1+' or '1-' for the charge on an ion. If only one electron is present in the half-cell reaction, type the answer as e- instead of 1e-.
Half-cell Equation
Au3+(aq) + 3 e¯ →
Au(s)
Typed Answer
Au3+(aq) + 3e- > Au(s)
Balanced Equation 2 Au3+(aq) + 3 Zn(s)
2 Au(s) + 3 Zn²+(aq)
Typed Answer
2AU3+(aq) + 3Zn(s) > 2Au(s) + 3Zn2+(aq)
(b) Write the half-cell reaction for the oxidation.
(c) Write the half-cell reaction for the reduction.
(d) Write the balanced equation for the cell reaction. Keep substances in the order given in the original equation.
O O O
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