A voltaic cell consists of a Pb/Pb2+ half-cell and a Cu/Cu2+ half-cell at 25 ∘C. The initial concentrations of Pb2+ and Cu2+ are 0.0520 M and 1.60 M , respectively.  a) What is the initial cell potential? Express your answer using two significant figures. b) What is the cell potential when the concentration of Cu2+ has fallen to 0.230 M ? Express your answer using two significant figures. c) What is the concentration of Pb2+ when the cell potential falls to 0.370 V ? Express your answer using three significant figures.

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Q: The answer is -1.98V

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A: Solution -

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Q: Calculate

A: