Two tangents intersect at station of 75+16.8, creating a 60° intersecting angle. A 6° simple horizontal curve is used to smooth the connection, determine the value of C2 required to set out the curve using Rankine's method Select one: O a. 35.8 m O b. 25.8 m O c. 30.8 m O d. 40 m

Two tangents intersect at station of 75+16.8, creating a 60° intersecting angle. A 6° simple horizontal curve is used to smooth the connection, determine the value of C2 required to set out the curve using Rankine's method Select one: O a. 35.8 m O b. 25.8 m O c. 30.8 m O d. 40 m

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

The long chord from the P.C to the P.T of a compound curve is 293.77 meters long and the angles its makes with the longer and shorter tangents are 13.94⁰ and 20.32° respectively. If the common tangent is parallel to the long chord, find the stationing of P.T. if the stationing of P.C. is 10 + 233.55. WRITE YOUR ANSWERS in meters. (For example, the stationing is 10+ 252.3 --> write this as 10252.3)
Station of the PI of the curve: 7+400 Elevation of the PI of the curve: 80m. L1 = 160m L2 = 120m G1 = +7% G2 = -4% a)Determine the elevation of the curve on every station starting from PC to PT. Tabulate your answer and show solutions.
A compound curve is having a common tangent of 84.50 meters long. The central angles made by the common tangent for the first and second simple curve is 16°and 20° respectively. The length of the tangent of the first curve is 38.60 meters and Sta. PI is 10+180. Determine: Length of Curve (Lc1) Length of Curve (Lc2) • Length of curve from PC to PT
Two roads AB and BC intersect at a chainage 184+65. These are intersected by a line PQ and the angles APQ and PQC are 112° and 102° respectively. The radius of the first arc of the curve is 330m and that of the second arc is 540m. Calculate the chainages of the first and the second tangent points P.C R₂ 2 P.T 185+87.15, 172+18.67 O 170+88.19, 182+14.97 O 176+48.69, 172+18.67 O 185+87.19, 152+14.97 O 190+84.32, 177+12.34 O
With the same problem, solve using this formulas. Draw the curve accurately.Additional Problem: L(Curve Length) = R x I (angle of intersection) x pi/180
Problem 4. Derive the expression for the offset y of any point of the curve above the beginning of a vertical curve that results in the following equation:
QUESTION 2 The tangent thru the PC has a direction due to North; and the tangent through the PT has a bearing of N 50° E. It has a radius of 200 m. Stationing of PC is 12+060. a. Compute the tangent distance of the curve. Answer: T= b. Compute the long chord of the curve. Answer: Lc = m m c. A line is drawn from the center of the curve (at the central angle) and intersects the curve at point B. This line, when extended, makes an angle of 62° with the tangent thru PC. What is the stationing of point B? Answer: Sta. B = Note: Unit has been provided after the blank space. No need to indicate units on your answer.
SITUATION 12: AB and BC are tangents of a simple curve. AB is due north and BC is N50°E. Degree of simple curve is 4° and PC is at station 20 + 130. 33. Compute the length of the long chord. a. 242.14 m c. 386.12 m d. 284.51 m b. 184.52 m 34. Compute the distance from point D on the simple curve to point of intersection of tangents that makes an angle of 54° with the tangent passing through the PC. а. 30.2 m b. 26.8 m С. 23.4 m d. 31.5 m 35. Compute the stationing of point D. a. 20 + 639.3 b. 20 + 739.3 c. 20 + 439.3 d. 20 + 249.3
Q1B) A circular horizontal curve having radius (R)=100 m and Deflection angle (0)= 60°. Compute the basic elements (L,LC,T,M,E) of the curve. gure below:
SITUATION 10: Two parallel tangents 12 m apart are connected by a reverse curve having equal radii. The long chord connecting the P.C to P.T is 140 m. 28. Determine the radius of the reverse curve. c. 200.41 m d. 512.41 m a. 408.33 m b. 813.64 m 29. Find the length of the curve. a. 175.75 m b. 131.29 m c. 279.30 m d. 140.17 m
Simple Curve A railway curve is to connect intersecting tangents with the following design data: Back tangent = N 20° 25' E Forward tangent = S 49°35' E Degree of curve = 5⁰ Design speed = 70 Kph Station PI = 5+555.55 1.Determine the length of line from PC to Pl. a) 234.67m b) 244.67m 2.Compute the straight distance from PC to PT. a) 402.34m b) 375.60m c) 245.89m d) 327.42m c) 389.78m d) 423.67m 3. If the width of the land intended for the railway is 10m, determine the area of land from PC to PT. a) 4,456.56 sqm b) 3,456,43 sqm c) 5,112.34 sqm d) 4,399.92 sqm 4.How long would a 300m long train able to leave the curve completely. a) 25.67 sec b) 38.06m sec c) 40.34 sec d) 29.67 sec