Assuming a reverse curve with the following parameters: Tangent @ Curve 1 = 40m Deflection Angle from PC to PRC = 60 degrees Stationing of the PC: 0+000 Tangent @Curve 1 = 50m Deflection Angle from PRC to PT = 50 degrees Using Deflection Angle Method, please provide comprehensive report on the layout of Reverse Horizontal Curve, with stationing of points in the curve at 10m interval.
Assuming a reverse curve with the following parameters: Tangent @ Curve 1 = 40m Deflection Angle from PC to PRC = 60 degrees Stationing of the PC: 0+000 Tangent @Curve 1 = 50m Deflection Angle from PRC to PT = 50 degrees Using Deflection Angle Method, please provide comprehensive report on the layout of Reverse Horizontal Curve, with stationing of points in the curve at 10m interval.
Traffic and Highway Engineering
5th Edition
ISBN:9781305156241
Author:Garber, Nicholas J.
Publisher:Garber, Nicholas J.
Chapter14: Highway Surveys And Location
Section: Chapter Questions
Problem 14P
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![Assuming a reverse curve with the following parameters:
Tangent @ Curve 1 = 40m
Deflection Angle from PC to PRC = 60 degrees
Stationing of the PC: 0+000
Tangent @Curve 1 = 50m
Deflection Angle from PRC to PT = 50 degrees
Using Deflection Angle Method, please provide comprehensive report on the layout of Reverse Horizontal Curve, with stationing of
points in the curve at 10m interval.
Use the editor to format your answer](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbb107e97-0152-47ac-833f-267d93f4bea0%2Fac528712-b136-49b6-b991-85f4bbf2da47%2Fh7strkb_processed.png&w=3840&q=75)
Transcribed Image Text:Assuming a reverse curve with the following parameters:
Tangent @ Curve 1 = 40m
Deflection Angle from PC to PRC = 60 degrees
Stationing of the PC: 0+000
Tangent @Curve 1 = 50m
Deflection Angle from PRC to PT = 50 degrees
Using Deflection Angle Method, please provide comprehensive report on the layout of Reverse Horizontal Curve, with stationing of
points in the curve at 10m interval.
Use the editor to format your answer
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Follow-up Questions
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Follow-up Question
With the same problem, solve using this formulas. Draw the curve accurately.
Additional Problem: L(Curve Length) = R x I (angle of intersection) x pi/180
![Degree of Arc basis
Chord Basis
R
R=
1145.916
D
10
sin](https://content.bartleby.com/qna-images/question/64ed0bb1-e3fd-4725-8910-3425ccad3eb3/d558fd1c-f449-4b47-b722-f8b93b4a500e/db6ahm2_thumbnail.jpeg)
Transcribed Image Text:Degree of Arc basis
Chord Basis
R
R=
1145.916
D
10
sin
![Tangent Distance
Middle Ordinate
External Distance
Long Chord
T = R tan (2)
M = R(1-cos(
(→))
E = R(sec() - 1)
Lc = 2R sin /
2](https://content.bartleby.com/qna-images/question/64ed0bb1-e3fd-4725-8910-3425ccad3eb3/d558fd1c-f449-4b47-b722-f8b93b4a500e/bcbtlbv_thumbnail.jpeg)
Transcribed Image Text:Tangent Distance
Middle Ordinate
External Distance
Long Chord
T = R tan (2)
M = R(1-cos(
(→))
E = R(sec() - 1)
Lc = 2R sin /
2
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