Two systems are formed from a converging lens and a diverging lens, as shown in parts a and b of the drawing. (The point labeled "Fconverging" is the focal point of the converging lens.) An object is placed inside the focal point of lens 1 at a distance of 10.00 cm to the left of lens 1. The focal lengths of the converging and diverging lenses are 15.00 and -20.0 cm, respectively. The distance between the lenses is 50.0 cm.
Q: A 1.00-cm-high object is placed 4.10 cm to the left of a converging lens of focal length 7.15 cm. A…
A: Image for editing due to lens 1 will be object for lens 2
Q: The figure below shows an object placed a distance do1 from one of two converging lenses separated…
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A: The formula for combination of two thin lenses: 1/F=(1/f1)+(1/f2)-(d/f1f2) as lens are in contact…
Q: Two convergent lenses, L1 (focal length = 15.6 cm) and L2 (focal length = 10.2 cm) are placed a…
A: 2 convex lenses distance "L" apart, Focal lengths, f1 = 15.6 cm f2 = 10.2 cm Object distance, u1 =…
Q: An object is 1.6 m to the left of a lens of focal length 0.64 m. A second lens of focal length -3.7…
A: To solve this problem, we can use the lens and magnification formulas for thin lenses. The lens…
Q: Two systems are formed from a converging lens and a diverging lens, as shown in parts a and b of the…
A: Given:converging lens focal length,fc = +15.0 cmdiverging lens focal length, fd = -20.0 cmdistamce…
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A: "Since you have posted a question with multiple sub-parts, we will solve first three sub-parts for…
Q: A lens forms an image of an object. The object is 16.0 cm from the lens. The image is 12.0 cm from…
A: The lens formula is a formula used in optics to calculate the relationship between the object…
Q: Two converging lenses are separated by 27.0 cm. The focal length of each lens is 17.0cm. An object…
A: GivenDistance of seperation between lens=27 cmFocal length of each lens=17 cmObject is placed to…
Q: A 1.20-cm-tall object is 50.0 cm to the left of a converging lens of focal length 40.0 cm. A second…
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Q: Three lenses are placed in a row, separated by 12 cm. The first lens is a diverging lens with focal…
A: The focal length of a diverging lens is negative and for converging lens it is positive.
Q: A diverging lense has a focal length of magnitude of 19.0 cm. Locate the image and magnification for…
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Q: 0 cm to the right of a diverging lens having a focal length of 12.0 cm. Determine the location of…
A: The diverging lens:- We know that the concave lens is the diverging lens, The refraction of light…
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A: We use the real is positive sign convention
Q: diverging lens is located 19 cm to the left of a converging lens. A 3.98-cm-tall object stands to…
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Q: An object is located 15.0 cm from a converging and unknown lens combination; the converging lens has…
A: useful formula:The u-v-f relation for a lens is1v-1u=1f--(1)v-image distanceu-object distancef-focal…
Q: A lens has one concave surface with a radius of curvature RA = 6.0 cm and one convex surface with…
A: Here R1= radius of curvature of first lens= -6 cm = -0.06 m ( as concave lens) R2= +8cm = 0.08 m .
Q: An object is placed distance so = 6.59 cm from a lens made from material with index of refraction…
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Q: Two lenses, one converging of focal length 10.0 cm and one diverging of 5.0 cm, are placed 30.0 cm…
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Q: a) An object is placed 40.0cm in front of a diverging lens with a focal length of 19.2 cm. Please…
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Q: Consider the optical system shown in the figure. The lens and mirror are separated by d = 1.00 m and…
A: (a) For the lens: f1 = 87.5 cm do1 = 1 m = 100 cm Using thin lens equation: 1/f1 = 1/do1 + 1/di1…
Q: A 2.0 cm tall object is 30 cm to the left of a lens with a focal length of 10 cm. A second lens…
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Q: An optical technician mounts two thin lenses along a single optical axis (the lenses are at right…
A: we know that Lens formula, 1f=1v-1uwhere, f is focal lengthand v is image distanceu is object…
Q: Two converging lenses, each of focal length 15.1 cm, are placed 40.0 cm apart, and an object is…
A: Given,focal length of lens 1, F1 = 15.1 cmfocal length of lens 2, F2 = 15.1 cmdistance between lens,…
Q: Figure QB1e shows the layout of a pair of lenses, lens 1 and lens 2. Lens 1 has a focal length of…
A: Lens formula: The lens formula is an equation which related the object distance, image distance, and…
Q: A diverging lens has a focal length of magnitude 19.6 cm. (a) Locate the images for each of the…
A: In this question we have to find the location and the magnification of the images formed by the…
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Q: Two lenses are mounted d = 39 cm apart on an optical bench. The focal length of the first lens is f1…
A: For the first case, the image distance is, 1v+1u=1fv=1f-1u-1 =19.8-124-1 =16.56 cm Now from lens…
Q: A compound lens system consists of two converging lenses, one at x=−20.0cm with focal length…
A: Given A compound lens system consists of two converging lenses position of lense-1: x=−20.0 cm focal…
Q: A 1.00-cm-high object is placed 4.95 cm to the left of a converging lens of focal length 7.75 cm. A…
A: Given information: The height of the object, ho=1.00 cm The distance of the object from the…
Q: A converging lens and a diverging lens, separated by a distance of 30.0 cm, are used in combination.…
A: Given: Object distance from conversing lens (uc) = -19.5 cm Focal length of…
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- An upright object is placed a distance in front of a converging lens equal to twicethe focal length of the lens. On the other side of the lens is a converging mirror of focallength , separated from the lens by a distance ; see diagram below. Find the location, nature, and relative size of the final image, as seen by an eye looking toward the mirrorthrough the lens. Draw the appropriate ray diagramFor safety reasons, you install a rear-window lens with a -0.299 m focal length in your van. Before putting the van in reverse, you look through the lens and see the image of a person who appears to be 0.339 m tall and 0.243 m behind the van. Determine the following. (a) actual distance of the person behind the van m (b) height of the personHomework 12 Problem 10: Two lenses are mounted d = 27 cm apart on an optical bench. The focal length of the first lens is f1 = 5.1 cm and that of the second lens is f2 = 4.4 cm. An object of height ho = 3.5 cm is placed at a distance of do = 21 cm in front of the first lens. Part (a) Ignoring the second lens for now, at what distance, in centimeters, behind the first lens is the object’s image formed by that lens? di = ______ Part (b) Calculate the magnification of that image, including its sign. m = ______ Part (c) Now consider the two-lens system and the final image it forms, i.e., the image created by the second lens. What is the distance, in centimeters, between the object and its final image? D = ______
- An object is 6 cm in front of a converging lens with a focal length of 10cm. Draw a ray diagram (to scale with a ruler) to find the location of the image. Is the image upright or inverted, and Is the image real or virtual? Then I want to use the thin lens formula to find the image distance and the magnification. I got stuck in the middle of this problem and am confused. Thank you for the help!An object of height 9.00 cm is placed 26.0 cm to the left of a converging lens with a focal length of 10.5 cm. Determine the image location in cm, the magnification, and the image height in cm. HINT (a) the image location in cm cm (b) the magnification (c) the image height in cm cm (d) Is the image real or virtual? real virtual (e) Is the image upright or inverted? upright invertedYou are tasked with sourcing a lens which will be made out of glass with refractive index 1.668, and is submersed in a liquid with refractive index 1.379. You want a focal length of 6.5 cm, and the radius of curvature of the first side of the lens is 7.4 cm. What radius of curvature is required for the second side, in cm? [Note the first/second lens surface radius is conventionally positive/negative for convex.]
- A system of two lenses forms an image of an arrow at x = x3 = 57.4 cm. The first lens is a diverging lens located at x = 0 and has a focal length of magnitude f₁ = 11.5 cm. The second lens is located at x = x₂ = 25.4 cm and has an unknown focal length. The tip of the object arrow is located at (x,y) = (xo, Yo) = (-36 cm, 20.6 cm). (x,y) 1) What is x₁, the x-coordinate of image of the arrow formed by the first lens? cm Submit 2) What is y₁, the y-coordinate of the image of the tip of the arrow formed by the first lens? cm Submit X₂ Real and Inverted Real and Upright Virtual and Inverted Virtual and Upright cm Submit (+) 3) What is f2, the focal length of the second lens. If the lens is a converging lens, f2 is positive. If the lens is a diverging lens, f2 is negative. cm Submit + 4) What is y3, the y-coordinate of the image of the tip of the arrow formed by the two lens system? (+ 5) The positions of the two lenses are now interchnaged (i.e., the second lens is moved to x = 0 and the…A 1.00-cm-high object is placed 4.35 cm to the left of a converging lens of focal length 8.20 cm. A diverging lens of focal length -16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position |-7.8 X cm in front of the second lens v height cm