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Two resistances, R₁ and R₂, are connected in series across a 12-V battery. The current increases by 0.18 A when R₂ is removed, leaving R₁ connected across the battery. However, the current increases by just 0.055 A when R₁ is removed, leaving R₂ connected across the battery. Find (a) R₁ and (b) R₂. R₁ R₁ ww R₂ www R2₂ ww

Two resistances, R₁ and R₂, are connected in series across a 12-V battery. The current increases by 0.18 A when R₂ is removed, leaving R₁ connected across the battery. However, the current increases by just 0.055 A when R₁ is removed, leaving R₂ connected across the battery. Find (a) R₁ and (b) R₂. R₁ R₁ ww R₂ www R2₂ ww

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Two resistances, R₁ and R₂, are connected in series across a 12-V battery. The current increases by 0.18 A when R₂ is removed, leaving R₁ connected across the battery. However, the current increases by just 0.055 A when R₁ is removed, leaving R₂ connected across the battery. Find (a) R₁ and (b) R₂. (a) Number (b) Number R₁ ww 11 remove R₂ Units Units R₁ V ◄► R₂ remove R₁ R₂ www 12 V
Transcribed Image Text:Two resistances, R₁ and R₂, are connected in series across a 12-V battery. The current increases by 0.18 A when R₂ is removed, leaving R₁ connected across the battery. However, the current increases by just 0.055 A when R₁ is removed, leaving R₂ connected across the battery. Find (a) R₁ and (b) R₂. (a) Number (b) Number R₁ ww 11 remove R₂ Units Units R₁ V ◄► R₂ remove R₁ R₂ www 12 V
Expert Solution
Step 1

Given,

Two resistance , R1 and R2 are connected in series across a 12-V battery.

The current increases by 0.18 A when R2 is removed leaving R1 connected across the battery.

The current increases by 0.055 A when R1 is removed leaving R2 connected.

Equivalent of R1 and R2 connected in series is equals to R1+R2.

We know that current = voltageResistance

Let 12 VR1+R2 = i

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