Two resistances, R₁ and R₂, are connected in series across a 12-V battery. The current increases by 0.29 A when R₂ is removed, leaving R₁ connected across the battery. However, the current increases by just 0.20 A when R₁ is removed, leaving R₂ connected across the battery. Find (a) R₁ and (b) R₂. شت ها R₁ www 41 V remove R₂ remove R₁ R₂ 12

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Two resistances, R₁ and R₂, are connected in series across a 12-V battery. The current increases by 0.29 A when R₂ is removed, leaving
R₁ connected across the battery. However, the current increases by just 0.20 A when R₁ is removed, leaving R₂ connected across the
battery. Find (a) R₁ and (b) R₂.
R₁
www
11
remove R₂
R₁
V
R₂
remove R₁
R₂
ww
12
Transcribed Image Text:Two resistances, R₁ and R₂, are connected in series across a 12-V battery. The current increases by 0.29 A when R₂ is removed, leaving R₁ connected across the battery. However, the current increases by just 0.20 A when R₁ is removed, leaving R₂ connected across the battery. Find (a) R₁ and (b) R₂. R₁ www 11 remove R₂ R₁ V R₂ remove R₁ R₂ ww 12
Expert Solution
Step 1

Given value---

  • V = 12 V.
  • when R2 remove.  then current increase by 0.29 A.
  • when R1 remove.  then current increase by 0.20 A.

We have to find---

  • R1 ?
  • R2 ?
steps

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