Two plates are kept separated by a film of oil of 0.025 mm. the top plate moves with a velocity of 50 cm/s while the bottom plate is kept fixed. Find the fluid viscosity of oil if the force required to move the plate is 0.2 kg/m2. P.1.2 If the equation of a velocity profile over a plate is u=3 y@a) in which the velocity in m/s at a distance y meters above the plate, determine the shear stress at y=0 and y=5 cm. Take u= 8.4 poise P.1.3 The equation of a velocity distribution over a plate is u=1/3 y y in which the velocity in m/s at a distance y meters above the plate, determine the shear stress at y=0 and y=0.1 m. Take u= 8.35 poise Ans. u= 9.81x10* Pa.s ? Ans. Tys0 = 00, Tyms = 4.56 Pa.s Ans. Tymo =2.78, Tymo,1= 4.56 dyne/cm

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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P.1.1
Two plates are kept separated by a film of oil of 0.025 mm. the top plate moves
with a velocity of 50 cm/s while the bottom plate is kept fixed. Find the fluid viscosity
of oil if the force required to move the plate is 0.2 kg/m².
P.1.2
If the equation of a velocity profile over a plate is u=3 y@a) in which the velocity
in m/s at a distance y meters above the plate, determine the shear stress at y=0 and y=5
cm. Take u= 8.4 poise
P.1.3
The equation of a velocity distribution over a plate is u=1/3 y y in which the
velocity in m/s at a distance y meters above the plate, determine the shear stress at y=0
and y=0.1 m. Take u= 8.35 poise
Ans. u= 9.81x10* Pa.s ?
Ans. Ty-o = 00, Tyms = 4.56 Pa.s
Ans. Ty-0 =2.78, ty-0,1= 4.56 dyne/cm
Transcribed Image Text:P.1.1 Two plates are kept separated by a film of oil of 0.025 mm. the top plate moves with a velocity of 50 cm/s while the bottom plate is kept fixed. Find the fluid viscosity of oil if the force required to move the plate is 0.2 kg/m². P.1.2 If the equation of a velocity profile over a plate is u=3 y@a) in which the velocity in m/s at a distance y meters above the plate, determine the shear stress at y=0 and y=5 cm. Take u= 8.4 poise P.1.3 The equation of a velocity distribution over a plate is u=1/3 y y in which the velocity in m/s at a distance y meters above the plate, determine the shear stress at y=0 and y=0.1 m. Take u= 8.35 poise Ans. u= 9.81x10* Pa.s ? Ans. Ty-o = 00, Tyms = 4.56 Pa.s Ans. Ty-0 =2.78, ty-0,1= 4.56 dyne/cm
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