Two-phase pipeline with 0.2 m diameter and 3000 m length. The inlet pressure = 2300 kPa, liquid flow rate = 0.01 m³/s, volumetric Gas Oil Ratio = 44, pu-680 kg/m³, pg-0.93 kg/m³, gas viscosity-0.015x10-³ Pa.s, and liquid viscosity = 9.4x103 Pa.s. If new gas pipeline with flow rate (0.09 m³/s) connects to the middle of the existing pipeline, calculate the pressure at the outlet of existing pipeline?

Elements Of Electromagnetics
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ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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Two-phase pipeline with 0.2 m diameter and 3000 m length. The inlet pressure = 2300 kPa, liquid flow rate
= 0.01 m³/s, volumetric Gas Oil Ratio = 44, pr-680 kg/m³, pg-0.93 kg/m³, gas viscosity-0.015x10-³ Pa.s, and
liquid viscosity = 9.4x103 Pa.s. If new gas pipeline with flow rate (0.09 m³/s) connects to the middle of the existing
pipeline, calculate the pressure at the outlet of existing pipeline?
Transcribed Image Text:Two-phase pipeline with 0.2 m diameter and 3000 m length. The inlet pressure = 2300 kPa, liquid flow rate = 0.01 m³/s, volumetric Gas Oil Ratio = 44, pr-680 kg/m³, pg-0.93 kg/m³, gas viscosity-0.015x10-³ Pa.s, and liquid viscosity = 9.4x103 Pa.s. If new gas pipeline with flow rate (0.09 m³/s) connects to the middle of the existing pipeline, calculate the pressure at the outlet of existing pipeline?
Expert Solution
Step 1: Given data

Given:

Pipeline diameter (D) = 0.2 m

Pipeline length (L) = 3000 m

Inlet pressure (P1) = 2300 kPa

Liquid flow rate (QL) = 0.01 m3/s

Volumetric Gas Oil Ratio (Rv) = 44

Liquid density (ρL) = 680 kg/m3

Gas density (ρgas) = 0.93 kg/m3

Gas viscosity (μgas) = 0.015x10^3 Pa.s

Liquid viscosity (μL) = 9.4x10^3 Pa.s

Gas flow rate in new pipeline (Qnew) = 0.09 m3/s

To find:

Pressure at outlet of existing pipeline (P2)


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