Two particles, one with charge -2.09 µC and one with charge 7.75 µC, are 2.09 cm apart. What is the magnitude of theforce that one particle exerts on the other?force:NTwo new particles, which have an identical positive charge q3, are placed the same 2.09 cm apart, and the force betweenthem is measured to be the same as that between the original particles. What is q3?93 =µC

Given, q1 = -2.09 μC = -2.09×10-6 Cq2 = 7.75 μC = 7.75×10-6 Cdistance r = 2.09 cm = 0.0209 m We…

Answered: Two particles, one with charge -2.09 µC…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

Two particles, one with charge -2.09 µC and one with charge 7.75 µC, are 2.09 cm apart. What is the magnitude of the
force that one particle exerts on the other?
force:
N
Two new particles, which have an identical positive charge q3, are placed the same 2.09 cm apart, and the force between
them is measured to be the same as that between the original particles. What is q3?
93 =
µC

Expert Solution

Step 1

Given,

$q_{1} = - 2.09 μC = - 2.09 \times 10^{- 6} C q_{2} = 7.75 μC = 7.75 \times 10^{- 6} C distance r = 2.09 cm = 0.0209 m$

We know the expression for coulomb's law is

$F = k \frac{|q_{1} q_{2}|}{r^{2}} F = \frac{(8.98 \times 10^{9}) \times |(- 2.09 \times 10^{- 6}) \times (7.75 \times 10^{- 6})|}{{(2.09 \times 10^{- 2})}^{2}} F = 333.60 N$

Therefore the magnitude of force is 333.60 N

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