confused ### Problem StatementParticle A of charge \(2.79 \times 10^{-4} \, \text{C}\) is at the origin, particle B of charge \(-6.54 \times 10^{-4} \, \text{C}\) is at (4.00 m, 0), and particle C of charge \(1.05 \times 10^{-4} \, \text{C}\) is at (0, 3.00 m). We wish to find the net electric force on C.---### Questions and Calculation Steps(a) **What is the x component of the electric force exerted by A on C?** \[ \text{Input box} \,\, (\text{N}) \](b) **What is the y component of the electric force exerted by A on C?** \[ \text{Input box} \,\, (\text{N}) \](c) **Find the magnitude of the force exerted by B on C.** \[ \text{Input box} \,\, (\text{N}) \](d) **Calculate the x component of the force exerted by B on C.** \[ \text{Input box} \,\, (\text{N}) \](e) **Calculate the y component of the force exerted by B on C.** \[ \text{Input box} \,\, (\text{N}) \](f) **Sum the two x components from parts (a) and (d) to obtain the resultant x component of the electric force acting on C.** \[ \text{Input box} \,\, (\text{N}) \](g) **Similarly, find the y component of the resultant force vector acting on C.** \[ \text{Input box} \,\, (\text{N}) \](h) **Find the magnitude and direction of the resultant electric force acting on C.** - Magnitude: \[ \text{Input box} \,\, (\text{N}) \] - Direction: \[ \text{Input box} \,\, (^\circ \, \text{counterclockwise from the} \, +\text{x-axis}) \]---### Need Help?[Read It]---### Explanation of Diagrams/GraphsThere are no diagrams or graphs in the provided content. However

Note:- You have posted multiple subparts question. As per guideline I will solve first three…

Particle A of charge 2.79 x 10-4 C is at the origin, particle B of charge -6.54 x 10-4 C is at (4.00 m, 0), and particle C of charge 1.05 x 10-4 C is at (0, 3.00 m). We wish to find the net electric force on C. (a) What is the x component of the electric force exerted by A on C? N (b) What is the y component of the force exerted by A on C? N (c) Find the magnitude of the force exerted by B on C. N