%3DA negative charge Q1 = -2 µC is fixed (cannot move) at the origin (x = 0).Another particle with a negative charge of Q2 = –1.5µC is released at x = 0.2 m with theinitial velocity of v = 3.0 m/s moving toward the +x direction. The electric force is the onlyforce exerted on the particle. The mass of the particle is 0.1 kg.%3D(a) What is the change of electric potential energy ofthe particle when the particle is very far away from Q1?x = 0x = 0.2 m(b) What is the speed of the particle when the particleis very far away from Q1?v = 3 m/sQ2Q1Change of the potential energy =Speed =1

The charge Q1 is at the origin, x=0 and Q2 is at x=0.2 mSo, Q2 is at a distance of 0.2 m from Q1At…

Answered: A negative charge Q1 = -2 µC is fixed…

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